Sli*_*169 3 string android json
我知道如何处理方法jsonObj.toString()但我有理由不能这样做.我的JSONObject里面有一个JSONArray,它有太多的数据,所以如果我将它转换为String然后转换回我害怕它达到String类型的限制.所以我想传递一个纯对象,而不是使用该方法.我实现Parcelable接口来做到这一点,但我得到错误" java.lang.RuntimeException:Parcel:无法编组值 "
public class MJSONObject implements Parcelable {
private JSONObject jsonObject;
public MJSONObject() {
}
public MJSONObject(JSONObject jsonObject) {
this.jsonObject = jsonObject;
}
public void set(JSONObject jsonObject) {
this.jsonObject = jsonObject;
}
public JSONObject get() {
return jsonObject;
}
@Override
public int describeContents() {
// TODO Auto-generated method stub
return 0;
}
public static final Parcelable.Creator<MJSONObject> CREATOR = new Parcelable.Creator<MJSONObject>() {
public MJSONObject createFromParcel(Parcel in) {
return new MJSONObject(in);
}
public MJSONObject[] newArray(int size) {
return new MJSONObject[size];
}
};
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeValue(jsonObject);
}
private MJSONObject(Parcel in) {
jsonObject = (JSONObject) in.readValue(JSONObject.class.getClassLoader());
}
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Zub*_*med 28
你可以轻松地通过JSONObject转换来传递你的内容,String就像在我们JSONObject使用url 发送的一些场景中一样,通过将其添加为String.所以,尝试发送它String像:
intent.putExtra("jsonObject", jsonObject.toString());
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并在另一边接收它
Intent intent = getIntent();
String jsonString = intent.getStringExtra("jsonObject");
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现在你有JSON一个String名字jsonString假设它作为一个响应,就像你从Web服务收到然后得到你的JSONObject喜欢:
JSONObject jObj = new JSONObject(jsonString);
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希望你能理解我的观点:)
试试这个,您还可以使用 ComplexPrefereces 类从一个活动获取对象到另一活动
在您的项目中添加 ComplexPreferences.java 类
import android.content.Context;
import android.content.SharedPreferences;
import com.google.gson.Gson;
import com.google.gson.reflect.TypeToken;
import java.lang.reflect.Type;
/**
* This class helps to store class object in the shared preferences
*
*/
public class ComplexPreferences {
private static ComplexPreferences complexPreferences;
private Context context;
private SharedPreferences preferences;
private SharedPreferences.Editor editor;
private static Gson GSON = new Gson();
Type typeOfObject = new TypeToken<Object>() {
}.getType();
private ComplexPreferences(Context context, String namePreferences, int mode) {
this.context = context;
if (namePreferences == null || namePreferences.equals("")) {
namePreferences = "complex_preferences";
}
preferences = context.getSharedPreferences(namePreferences, mode);
editor = preferences.edit();
}
public static ComplexPreferences getComplexPreferences(Context context,
String namePreferences, int mode) {
if (complexPreferences == null) {
complexPreferences = new ComplexPreferences(context,
namePreferences, mode);
}
return complexPreferences;
}
public void putObject(String key, Object object) {
if(object == null){
throw new IllegalArgumentException("object is null");
}
if(key.equals("") || key == null){
throw new IllegalArgumentException("key is empty or null");
}
editor.putString(key, GSON.toJson(object));
}
public void commit() {
editor.commit();
}
public <T> T getObject(String key, Class<T> a) {
String gson = preferences.getString(key, null);
if (gson == null) {
return null;
} else {
try{
return GSON.fromJson(gson, a);
} catch (Exception e) {
throw new IllegalArgumentException("Object storaged with key " + key + " is instanceof other class");
}
}
}
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}
将对象存储在共享首选项中,如下所示:
ComplexPreferences complexPreferences = ComplexPreferences.getComplexPreferences(getActivity(), "store_object", 0);
complexPreferences.putObject("class_name", className);
complexPreferences.commit();
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为了检索返回对象,如下所示:
ComplexPreferences complexPreferences = ComplexPreferences.getComplexPreferences(DrawerActivity.this, "store_object", 0);
ClassName className=complexPreferences.getObject("class_name", ClassName.class);
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