来自Swift Range的NSRange?

Jay*_*Jay 153 macos ios nsrange swift

问题:当我使用使用Range的Swift String时,NSAttributedString接受NSRange

let text = "Long paragraph saying something goes here!"
let textRange = text.startIndex..<text.endIndex
let attributedString = NSMutableAttributedString(string: text)

text.enumerateSubstringsInRange(textRange, options: NSStringEnumerationOptions.ByWords, { (substring, substringRange, enclosingRange, stop) -> () in

    if (substring == "saying") {
        attributedString.addAttribute(NSForegroundColorAttributeName, value: NSColor.redColor(), range: substringRange)
    }
})
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产生以下错误:

错误:'Range'不能转换为'NSRange'aligolsString.addAttribute(NSForegroundColorAttributeName,value:NSColor.redColor(),range:substringRange)

Mar*_*n R 241

Swift String范围和NSString范围不是"兼容的".例如,表情符号就像一个Swift字符,但是作为两个NSString 字符(所谓的UTF-16代理对).

因此,如果字符串包含此类字符,则建议的解决方案将产生意外结果 例:

let text = "Long paragraph saying!"
let textRange = text.startIndex..<text.endIndex
let attributedString = NSMutableAttributedString(string: text)

text.enumerateSubstringsInRange(textRange, options: NSStringEnumerationOptions.ByWords, { (substring, substringRange, enclosingRange, stop) -> () in
    let start = distance(text.startIndex, substringRange.startIndex)
    let length = distance(substringRange.startIndex, substringRange.endIndex)
    let range = NSMakeRange(start, length)

    if (substring == "saying") {
        attributedString.addAttribute(NSForegroundColorAttributeName, value: NSColor.redColor(), range: range)
    }
})
println(attributedString)
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输出:

Long paragra{
}ph say{
    NSColor = "NSCalibratedRGBColorSpace 1 0 0 1";
}ing!{
}

如你所见,"ph say"已经标有属性,而不是"说".

由于NS(Mutable)AttributedString最终需要a NSString和a NSRange,实际上最好将给定的字符串转换为NSString第一个.然后substringRange 是一个NSRange,您不必再转换范围:

let text = "Long paragraph saying!"
let nsText = text as NSString
let textRange = NSMakeRange(0, nsText.length)
let attributedString = NSMutableAttributedString(string: nsText)

nsText.enumerateSubstringsInRange(textRange, options: NSStringEnumerationOptions.ByWords, { (substring, substringRange, enclosingRange, stop) -> () in

    if (substring == "saying") {
        attributedString.addAttribute(NSForegroundColorAttributeName, value: NSColor.redColor(), range: substringRange)
    }
})
println(attributedString)
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输出:

Long paragraph {
}saying{
    NSColor = "NSCalibratedRGBColorSpace 1 0 0 1";
}!{
}

Swift 2更新:

let text = "Long paragraph saying!"
let nsText = text as NSString
let textRange = NSMakeRange(0, nsText.length)
let attributedString = NSMutableAttributedString(string: text)

nsText.enumerateSubstringsInRange(textRange, options: .ByWords, usingBlock: {
    (substring, substringRange, _, _) in

    if (substring == "saying") {
        attributedString.addAttribute(NSForegroundColorAttributeName, value: NSColor.redColor(), range: substringRange)
    }
})
print(attributedString)
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Swift 3更新:

let text = "Long paragraph saying!"
let nsText = text as NSString
let textRange = NSMakeRange(0, nsText.length)
let attributedString = NSMutableAttributedString(string: text)

nsText.enumerateSubstrings(in: textRange, options: .byWords, using: {
    (substring, substringRange, _, _) in

    if (substring == "saying") {
        attributedString.addAttribute(NSForegroundColorAttributeName, value: NSColor.red, range: substringRange)
    }
})
print(attributedString)
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Swift 4的更新:

从Swift 4(Xcode 9)开始,Swift标准库提供了在Range<String.Index>和之间进行转换的方法NSRange.NSString不再需要转换为:

let text = "Long paragraph saying!"
let attributedString = NSMutableAttributedString(string: text)

text.enumerateSubstrings(in: text.startIndex..<text.endIndex, options: .byWords) {
    (substring, substringRange, _, _) in
    if substring == "saying" {
        attributedString.addAttribute(.foregroundColor, value: NSColor.red,
                                      range: NSRange(substringRange, in: text))
    }
}
print(attributedString)
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substringRange是一个Range<String.Index>,并将其转换为相应NSRange

NSRange(substringRange, in: text)
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  • 对于想要在OSX上键入表情符号字符的任何人 - 控制 - 命令空间栏会显示一个字符选择器 (70认同)
  • 如果我匹配多个单词,这不起作用,我不确定要匹配的整个字符串是什么.假设我从API返回一个字符串并在另一个字符串中使用它,我希望API中的字符串加下划线,我不能保证子字符串不会出现在API的字符串和其他字符串中串!有任何想法吗? (2认同)
  • 你提到`Range <String.Index>`和`NSString`是不兼容的.他们的同行也不相容吗?即`NSRange`和`String`不兼容?因为Apple的API之一特别结合了两者:[matches(in:options:range:)](https://developer.apple.com/reference/foundation/nsregularexpression/1412446-matches) (2认同)

roy*_*rma 53

对于像你描述的那样的情况,我发现这是有用的.它相对简短而且甜美:

 let attributedString = NSMutableAttributedString(string: "follow the yellow brick road") //can essentially come from a textField.text as well (will need to unwrap though)
 let text = "follow the yellow brick road"
 let str = NSString(string: text) 
 let theRange = str.rangeOfString("yellow")
 attributedString.addAttribute(NSForegroundColorAttributeName, value: UIColor.yellowColor(), range: theRange)
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  • attributionString.addAttribute不适用于swift Range (9认同)
  • @Paludis,你是对的,但这个解决方案并没有尝试使用Swift系列.它使用的是"NSRange".`str`是一个`NSString`,因此`str.RangeOfString()`返回一个`NSRange`. (6认同)
  • 你也可以删除第2行中的重复字符串,方法是将第2行和第3行替换为:`let str = attributionString.string as NSString` (3认同)
  • 这是本地化的噩梦。 (2认同)

Geo*_*dze 23

答案很好,但使用Swift 4可以简化代码:

let text = "Test string"
let substring = "string"

let substringRange = text.range(of: substring)!
let nsRange = NSRange(substringRange, in: text)
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请注意,因为range功能的结果必须打开.


Jay*_*Jay 10

可能解决方案

Swift提供distance(),用于测量可用于创建NSRange的start和end之间的距离:

let text = "Long paragraph saying something goes here!"
let textRange = text.startIndex..<text.endIndex
let attributedString = NSMutableAttributedString(string: text)

text.enumerateSubstringsInRange(textRange, options: NSStringEnumerationOptions.ByWords, { (substring, substringRange, enclosingRange, stop) -> () in
    let start = distance(text.startIndex, substringRange.startIndex)
    let length = distance(substringRange.startIndex, substringRange.endIndex)
    let range = NSMakeRange(start, length)

//    println("word: \(substring) - \(d1) to \(d2)")

        if (substring == "saying") {
            attributedString.addAttribute(NSForegroundColorAttributeName, value: NSColor.redColor(), range: range)
        }
})
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  • 注意:如果在字符串中使用像表情符号这样的字符,这可能会中断 - 请参阅Martin的回复. (2认同)

Dha*_*ena 8

斯威夫特 5 解决方案

将范围转换为 NSRange

由于'encodedOffset'已被弃用,因此现在为了将String.Index转换为Int ,我们需要派生Range<String.Index>的原始字符串的引用。

NSRange 的方便详细扩展如下:

extension NSRange {

    public init(range: Range<String.Index>, 
                originalText: String) {

        let range_LowerBound_INDEX = range.lowerBound
        let range_UpperBound_INDEX = range.upperBound

        let range_LowerBound_INT = range_LowerBound_INDEX.utf16Offset(in: originalText)
        let range_UpperBound_INT = range_UpperBound_INDEX.utf16Offset(in: originalText)

        let locationTemp = range_LowerBound_INT
        let lengthTemp = range_UpperBound_INT - range_LowerBound_INT

        self.init(location: locationTemp,
                  length: lengthTemp)
    }
}
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虽然简写扩展如下

extension NSRange {

    public init(range: Range<String.Index>, 
                originalText: String) {

        self.init(location: range.lowerBound.utf16Offset(in: originalText),
                  length: range.upperBound.utf16Offset(in: originalText) - range.lowerBound.utf16Offset(in: originalText))
    }
}

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现在我们可以使用任何 Range 将其转换为 NSRange,如下所示,分享我自己的要求,这导致我编写了上面的扩展

我使用下面的字符串扩展来查找字符串中特定单词的所有范围

extension String {
        
    func ranges(of substring: String, options: CompareOptions = [], locale: Locale? = nil) -> [Range<Index>] {
        var ranges: [Range<Index>] = []
        while let range = range(of: substring, options: options, range: (ranges.last?.upperBound ?? self.startIndex)..<self.endIndex, locale: locale) {
            ranges.append(range)
        }
        return ranges
    }
}

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我的要求是更改字符串中特定单词的颜色,因此我编写了这个扩展来完成这项工作

extension NSAttributedString {

    static func colored(originalText:String,
                        wordToColor:String,
                        currentColor:UIColor,
                        differentColor:UIColor) -> NSAttributedString {
        
        let attr = NSMutableAttributedString(string: originalText)
        
        attr.beginEditing()
        
        attr.addAttribute(NSAttributedString.Key.foregroundColor,
                          value: currentColor,
                          range: NSRange(location: 0, length: originalText.count))
        
        // FOR COVERING ALL THE OCCURENCES
        for eachRange in originalText.ranges(of: wordToColor) {
            attr.addAttribute(NSAttributedString.Key.foregroundColor,
                              value: differentColor,
                              range: NSRange(range: eachRange, originalText: originalText))
        }
        
        attr.endEditing()
        
        return attr
    }

}
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最后我从我的主要代码中使用它,如下所示

let text = "Collected".localized() + "  +  " + "Cancelled".localized() + "  +  " + "Pending".localized()
myLabel.attributedText = NSAttributedString.colored(originalText: text,
                                                    wordToColor: "+",
                                                    currentColor: UIColor.purple,
                                                    differentColor: UIColor.blue)

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结果如下,+号的颜色从紫色的正文颜色变成了蓝色。

在此输入图像描述

希望这可以帮助有需要的人。谢谢!


小智 6

对我来说,这很完美:

let font = UIFont.systemFont(ofSize: 12, weight: .medium)
let text = "text"
let attString = NSMutableAttributedString(string: "exemple text :)")

attString.addAttributes([.font: font], range:(attString.string as NSString).range(of: text))

label.attributedText = attString
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Dmi*_* A. 5

斯威夫特4:

当然,我知道Swift 4已经扩展了NSRange

public init<R, S>(_ region: R, in target: S) where R : RangeExpression,
    S : StringProtocol, 
    R.Bound == String.Index, S.Index == String.Index
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我知道在大多数情况下这个初始化就足够了.看它的用法:

let string = "Many animals here:  !!!"

if let range = string.range(of: ""){
     print((string as NSString).substring(with: NSRange(range, in: string))) //  ""
 }
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但转换可以直接从Range <String.Index>到NSRange完成而不需要Swift的String实例.

而不是通用的init用法,它要求您将目标参数作为String,如果您没有目标字符串,则可以直接创建转换

extension NSRange {
    public init(_ range:Range<String.Index>) {
        self.init(location: range.lowerBound.encodedOffset,
              length: range.upperBound.encodedOffset -
                      range.lowerBound.encodedOffset) }
    }
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或者您可以为Range本身创建专门的扩展

extension Range where Bound == String.Index {
    var nsRange:NSRange {
    return NSRange(location: self.lowerBound.encodedOffset,
                     length: self.upperBound.encodedOffset -
                             self.lowerBound.encodedOffset)
    }
}
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用法:

let string = "Many animals here:  !!!"
if let range = string.range(of: ""){
    print((string as NSString).substring(with: NSRange(range))) //  ""
}
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要么

if let nsrange = string.range(of: "")?.nsRange{
    print((string as NSString).substring(with: nsrange)) //  ""
}
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Den*_*Den 5

雨燕4

我认为,有两种方法。

1. NSRange(范围,在: )

2. NSRange(位置:,长度:)

示例代码:

let attributedString = NSMutableAttributedString(string: "Sample Text 12345", attributes: [.font : UIFont.systemFont(ofSize: 15.0)])

// NSRange(range, in: )
if let range = attributedString.string.range(of: "Sample")  {
    attributedString.addAttribute(.foregroundColor, value: UIColor.orange, range: NSRange(range, in: attributedString.string))
}

// NSRange(location: , length: )
if let range = attributedString.string.range(of: "12345") {
    attributedString.addAttribute(.foregroundColor, value: UIColor.green, range: NSRange(location: range.lowerBound.encodedOffset, length: range.upperBound.encodedOffset - range.lowerBound.encodedOffset))
}
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截屏: 在此输入图像描述