Python:TypeError:此构造函数不带参数

Question

当用户输入电子邮件地址时,程序会读取电子邮件并根据其标准(例如yeo.myy@edu.co)显示电子邮件,如标准:

• username 是 yeo.myy
• domain 是 edu.co

我知道它与它有关"@".

这是代码

class Email:
    def __int__(self,emailAddr):
        self.emailAddr = emailAddr


    def domain(self):
        index = 0
        for i in range(len(emailAddr)):
            if emailAddr[i] == "@":
                index = i
            return self.emailAddr[index+1:]

    def username(self):
        index = 0
        for i in range(len(emailAddr)):
            if emailAddr[i] == "@" :
                index = i
            return self.emailAddr[:index]

def main():

    emailAddr = raw_input("Enter your email>>")

    user = Email(emailAddr)

    print "Username = ", user.username()
    print "Domain = ", user.domain()

main()

这是我得到的错误:

Traceback (most recent call last):
  File "C:/Users/Owner/Desktop/sdsd", line 29, in <module>
    main()
  File "C:/Users/Owner/Desktop/sdsd", line 24, in main
    user = Email(emailAddr)
TypeError: this constructor takes no arguments

Answer 1

def __int__(self,emailAddr):

你的意思是__init__？

def __init__(self,emailAddr):

你的方法中也缺少一些self,你的returns缩进不正确.

def domain(self):
    index = 0
    for i in range(len(self.emailAddr)):
        if self.emailAddr[i] == "@":
            index = i
            return self.emailAddr[index+1:]

def username(self):
    index = 0
    for i in range(len(self.emailAddr)):
        if self.emailAddr[i] == "@" :
            index = i
            return self.emailAddr[:index]

结果:

Username =  yeo.myy
Domain =  edu.co

顺便提一下,我建议partition并rpartition在给定的分隔符上将字符串拆分为两个部分.当然可以手动跟踪指数.

def domain(self):
    return self.emailAddr.rpartition("@")[2]
def username(self):
    return self.emailAddr.rpartition("@")[0]