Python查找列表的最小最大值和平均值(数组)

Question

我很难弄清楚如何从列表中找到min例如

somelist = [1,12,2,53,23,6,17]

如何使用define(def)函数找到此列表的最小值和最大值

我不想使用内置函数 min

Answer 1

from __future__ import division

somelist =  [1,12,2,53,23,6,17] 
max_value = max(somelist)
min_value = min(somelist)
avg_value = sum(somelist)/len(somelist)

如果要手动查找最小值作为函数:

somelist =  [1,12,2,53,23,6,17] 

def my_min_function(somelist):
    min_value = None
    for value in somelist:
        if not min_value:
            min_value = value
        elif value < min_value:
            min_value = value
    return min_value

Python 3.4引入了statistics包,它提供了mean额外的统计信息:

from statistics import mean, median

somelist =  [1,12,2,53,23,6,17]
avg_value = mean(somelist)
median_value = median(somelist)

Answer 2

返回元组中的最小值和最大值：

def side_values(num_list):
    results_list = sorted(num_list)
    return results_list[0], results_list[-1]


somelist = side_values([1,12,2,53,23,6,17])
print(somelist)