如何序列化boost :: uuid与谷类食品

Question

尝试序列化此简单类：

class Data
{
public:
    Data();
    Data(boost::uuids::uuid id);

    Data(const Data&) = delete;
    Data& operator=(const Data&) = delete;

    inline boost::uuids::uuid getGuid() { return guid; }

    template <class Archive>
    void serialize(Archive & ar)
    {
        ar(guid);
    }

private:
    boost::uuids::uuid guid;
};

但我收到此错误消息

error C2338: Trying to serialize an unserializable type with an output archive. 

潜伏到uuid。实现此目的的Boost序列化方法是添加

#include <boost/uuid/uuid_serialize.hpp>

但这不适用于开箱即用的谷物。谷物文件说

谷物存档在std :: ostream或std :: istream对象上运行。

所以我尝试在已定义但没有运气的地方添加标题

#include <boost/uuid/uuid_io.hpp>

Answer 1

这适用于谷物JSON档案。我还在评论中包括了一种用于二进制存档的方法。

#ifndef CEREAL_TYPES_BOOST_UUID_
#define CEREAL_TYPES_BOOST_UUID_

#include <boost/uuid/uuid.hpp>
#include <boost/uuid/uuid_io.hpp>
#include <boost/lexical_cast.hpp>

namespace cereal
{
    template <class Archive> inline
        void save(Archive& ar, boost::uuids::uuid const& uuid)
    {
        std::string val = boost::lexical_cast<std::string>(uuid);

        ar(val);

        // Other approach, probably better for binary
        //ar(make_size_tag(static_cast<size_type>(uuid.size())));
        //for (auto it = uuid.begin(), end = uuid.end(); it != end; ++it)
        //  ar(*it);
    }

    template <class Archive> inline
        void load(Archive& ar, boost::uuids::uuid& uuid)
    {
        std::string val;

        ar(val);
        uuid = boost::lexical_cast<boost::uuids::uuid>(val);

        // Other approach, probably better for binary
        //size_type size;
        //ar(make_size_tag(size));

        //for (auto it = uuid.begin(), end = uuid.end(); it != end; ++it) {
        //  uint8_t val;
        //  ar(val);
        //  *it = val;
        //}
    }
} // namespace cereal

#endif // CEREAL_TYPES_BOOST_UUID_