Kon*_*rad 4 python string markup beautifulsoup html-parsing
是否可以将标记设置为标记内容(类似于innerHtmlJavaScript中的设置)？
举个例子,假设我想在a中添加10个<a>元素<div>,但用逗号分隔:
soup = BeautifulSoup(<<some document here>>)
a_tags = ["<a>1</a>", "<a>2</a>", ...] # list of strings
div = soup.new_tag("div")
a_str = ",".join(a_tags)
使用div.append(a_str)逃逸<和>成<和>,所以我结束了
<div> <a1> 1 </a> ... </div>
BeautifulSoup(a_str)把它包裹起来<html>,我看到把树当作一个不雅的黑客.
该怎么办？
您需要BeautifulSoup从HTML包含链接的字符串中创建一个对象:
from bs4 import BeautifulSoup
soup = BeautifulSoup()
div = soup.new_tag('div')
a_tags = ["<a>1</a>", "<a>2</a>", "<a>3</a>", "<a>4</a>", "<a>5</a>"]
a_str = ",".join(a_tags)
div.append(BeautifulSoup(a_str, 'html.parser'))
soup.append(div)
print soup
打印:
<div><a>1</a>,<a>2</a>,<a>3</a>,<a>4</a>,<a>5</a></div>
替代方案:
对于每个链接创建一个Tag并附加到它div.另外,在除最后一个之外的每个链接后附加一个逗号:
from bs4 import BeautifulSoup
soup = BeautifulSoup()
div = soup.new_tag('div')
for x in xrange(1, 6):
link = soup.new_tag('a')
link.string = str(x)
div.append(link)
# do not append comma after the last element
if x != 6:
div.append(",")
soup.append(div)
print soup
打印:
<div><a>1</a>,<a>2</a>,<a>3</a>,<a>4</a>,<a>5</a></div>