dev*_*jim 6 django django-rest-framework
这是我的代码:
class UserSerializer(serializers.ModelSerializer):
class Meta:
model = User
fields = ( 'username', 'email')
class AllListingSerializer(serializers.ModelSerializer):
class Meta:
model = Listing
fields = ('name', 'desc', 'thumbnail', 'office_no', 'mobile_no', 'email', 'web ')
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class UserViewSet(generics.ListCreateAPIView):
queryset = User.objects.all()
serializer_class = UserSerializer
class AllListing(generics.ListCreateAPIView):
queryset = Listing.objects.all()
serializer_class = AllListingSerializer
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urlpatterns = patterns('',
url(r'^$', apiview.UserViewSet),
url(r'^listings/$', apiview.AllListing),
)
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但是当我转到它显示的基本网址时
init()接受1个位置参数,但给出2个
当我转到'/ listings /'网址时,它会给我404 Page Not Found,但我在db中的列表很少.
我在django很新.我无法弄清楚他们有什么问题.我在virtualwrappr,python 3.4中使用Django 1.7.1.
您应该调用.as_view()每个API视图:
urlpatterns = patterns('',
url(r'^$', apiview.UserViewSet.as_view()),
url(r'^listings/$', apiview.AllListing.as_view()),
)
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此外,请考虑使用REST框架Routers,它为您提供了一种简单,快速和一致的方法,将您的视图逻辑连接到一组URL.
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