迭代ruby中的哈希数组

Question

所以,如果我有一个像这样的哈希数组:(红宝石初学者)

input =  [

{"last_name"=>"Gay", "first_name"=>"Rudy", "display_name"=>"Rudy Gay", "position"=>"SF", "minutes"=>39, "points"=>25, "assists"=>6}, 
{"last_name"=>"Collison", "first_name"=>"Darren", "display_name"=>"Darren Collison", "position"=>"PG", "minutes"=>39, "points"=>14, "assists"=>4}

]

我将如何遍历数组以及迭代每个哈希以得到类似这样的东西:

player1 = {display_name =>"rudy gay","position"=>"SF"}

player2 = {display_name =>"darren collison","position"=>"PG"}

它会是什么样的

input.each do  |x|
Player.create(name: x['display_name'], position: x['position']
end

(假设我有一个玩家模型)

有没有更好的方法来实现这一目标？

谢谢!

Answer 1

鉴于您的意见:

input =  [
  { "last_name"=>"Gay", ... }, 
  { "last_name"=>"Collison", ...}
]

如果Player模型中存在所有这些键(last_name,first_name,display_name),您可以:

input.each do |x|
  Player.create(x)
end

因为create将采用散列属性来分配.但是,更好的是,你甚至不需要迭代:

Player.create(input)

如果你给它一个哈希数组,ActiveRecord将全部通过它们.