BitmapFactory.decodeFile()中的OutOfMemoryError

Question

当我从图库中选择图像时,如果图像大小超过3 Mb android的OutOfMemoryError.

 BitmapFactory.Options options = new BitmapFactory.Options();
        options.inPreferredConfig = Bitmap.Config.ARGB_8888;
        Bitmap bmp = BitmapFactory.decodeFile(imageFilePath, options);

这个文本来自日志.请帮助我,因为"截止日期")

E/AndroidRuntime? FATAL EXCEPTION: main
java.lang.OutOfMemoryError
        at android.graphics.BitmapFactory.nativeDecodeStream(Native Method)
        at android.graphics.BitmapFactory.decodeStream(BitmapFactory.java:623)
        at android.graphics.BitmapFactory.decodeFile(BitmapFactory.java:378)
        at com.DriverNotes.AndroidMobileClientTest.ProfileActivity.onActivityResult(ProfileActivity.java:104)
        at android.app.Activity.dispatchActivityResult(Activity.java:5456)
        at android.app.ActivityThread.deliverResults(ActivityThread.java:3402)
        at android.app.ActivityThread.handleSendResult(ActivityThread.java:3449)
        at android.app.ActivityThread.access$1200(ActivityThread.java:150)
        at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1328)
        at android.os.Handler.dispatchMessage(Handler.java:99)
        at android.os.Looper.loop(Looper.java:137)

Answer 1

当您的应用程序超出堆中分配的内存时,会发生OutofMemory.位图太大而无法放入内存即堆中.在这种情况下,你的内存不足.您需要缩小位图然后使用相同的位图.

为此检查此链接

试试这段代码可以帮到你,

 public static Bitmap decodeFile(File f,int WIDTH,int HIGHT){
 try {
     //Decode image size
     BitmapFactory.Options o = new BitmapFactory.Options();
     o.inJustDecodeBounds = true;
     BitmapFactory.decodeStream(new FileInputStream(f),null,o);

     //The new size we want to scale to
     final int REQUIRED_WIDTH=WIDTH;
     final int REQUIRED_HIGHT=HIGHT;
     //Find the correct scale value. It should be the power of 2.
     int scale=1;
     while(o.outWidth/scale/2>=REQUIRED_WIDTH && o.outHeight/scale/2>=REQUIRED_HIGHT)
         scale*=2;

     //Decode with inSampleSize
     BitmapFactory.Options o2 = new BitmapFactory.Options();
     o2.inSampleSize=scale;
     return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
 } catch (FileNotFoundException e) {}
 return null;
}

Answer 2

BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 8;
Bitmap bm = BitmapFactory.decodeFile(path,options);