Zhu*_*arb 11 python concatenation time-series pandas
在过去的几天里,这一直是我生命中的祸根.我有许多Pandas Dataframes包含不规则频率的时间序列数据.我尝试将这些对齐到一个数据帧中.
下面是一些代码,具有代表性的dataframes, ,df1,df2和df3(其实我的n = 5,并希望得到一个解决方案,将所有的工作n>2):
# df1, df2, df3 are given at the bottom
import pandas as pd
import datetime
# I can align df1 to df2 easily
df1aligned, df2aligned = df1.align(df2)
# And then concatenate into a single dataframe
combined_1_n_2 = pd.concat([df1aligned, df2aligned], axis =1 )
# Since I don't know any better, I then try to align df3 to combined_1_n_2 manually:
combined_1_n_2.align(df3)
error: Reindexing only valid with uniquely valued Index objects
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我知道为什么我得到这个错误,所以我摆脱了重复的索引,combined_1_n_2然后再试一次:
combined_1_n_2 = combined_1_n_2.groupby(combined_1_n_2.index).first()
combined_1_n_2.align(df3) # But stll get the same error
error: Reindexing only valid with uniquely valued Index objects
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为什么我收到此错误?即使这有效,它也完全是手工和丑陋的.如何对齐> 2个时间序列并将它们组合在一个数据帧中?
数据:
df1 = pd.DataFrame( {'price' : [62.1250,62.2500,62.2375,61.9250,61.9125 ]},
index = [pd.DatetimeIndex([datetime.datetime.strptime(s, '%Y-%m-%d %H:%M:%S.%f')])[0]
for s in ['2008-06-01 06:03:59.614000', '2008-06-01 06:03:59.692000',
'2008-06-01 06:15:42.004000', '2008-06-01 06:15:42.083000','2008-06-01 06:17:01.654000' ] ])
df2 = pd.DataFrame({'price': [241.0625, 241.5000, 241.3750, 241.2500, 241.3750 ]},
index = [pd.DatetimeIndex([datetime.datetime.strptime(s, '%Y-%m-%d %H:%M:%S.%f')])[0]
for s in ['2008-06-01 06:13:34.524000', '2008-06-01 06:13:34.602000',
'2008-06-01 06:15:05.399000', '2008-06-01 06:15:05.399000','2008-06-01 06:15:42.082000' ] ])
df3 = pd.DataFrame({'price': [67.656, 67.875, 67.8125, 67.75, 67.6875 ]},
index = [pd.DatetimeIndex([datetime.datetime.strptime(s, '%Y-%m-%d %H:%M:%S.%f')])[0]
for s in ['2008-06-01 06:03:52.281000', '2008-06-01 06:03:52.359000',
'2008-06-01 06:13:34.848000', '2008-06-01 06:13:34.926000','2008-06-01 06:15:05.321000' ] ])
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您的具体错误是由于列名combined_1_n_2具有重复项(两列都将命名为"price").您可以重命名列,第二个对齐也可以.
一种替代方法是链接join运算符,该运算符合并索引上的帧,如下所示.
In [23]: df1.join(df2, how='outer', rsuffix='_1').join(df3, how='outer', rsuffix='_2')
Out[23]:
price price_1 price_2
2008-06-01 06:03:52.281000 NaN NaN 67.6560
2008-06-01 06:03:52.359000 NaN NaN 67.8750
2008-06-01 06:03:59.614000 62.1250 NaN NaN
2008-06-01 06:03:59.692000 62.2500 NaN NaN
2008-06-01 06:13:34.524000 NaN 241.0625 NaN
2008-06-01 06:13:34.602000 NaN 241.5000 NaN
2008-06-01 06:13:34.848000 NaN NaN 67.8125
2008-06-01 06:13:34.926000 NaN NaN 67.7500
2008-06-01 06:15:05.321000 NaN NaN 67.6875
2008-06-01 06:15:05.399000 NaN 241.3750 NaN
2008-06-01 06:15:05.399000 NaN 241.2500 NaN
2008-06-01 06:15:42.004000 62.2375 NaN NaN
2008-06-01 06:15:42.082000 NaN 241.3750 NaN
2008-06-01 06:15:42.083000 61.9250 NaN NaN
2008-06-01 06:17:01.654000 61.9125 NaN NaN
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