Ang*_*era 2 java search arraylist
例如我想搜索代码A25和A29那么它会打印出来吗?我似乎找不到在arraylist中搜索长单词的语法.
ArrayList<String> arrList = new ArrayList<String>();
arrList.add("A25 CS 212 Data Structures 3");
arrList.add("A26 IT 312 Data Base Management System 2 3");
arrList.add("A27 IT 312 Data Base Management System 2 3");
arrList.add("A28 IT 212 Data Base Management System 2 3");
arrList.add("A29 CS 313 Digital Design 3");
arrList.add("A30 IT 212 Discrete Structures 3");
arrList.add("A25 IT 212 Discrete Structures 3");
arrList.add("984 Engl 3 Speech and oral Communication 3");
arrList.add("582 Theo 3 Christ and Sacraments 3");
arrList.add("470 Stata1 Probablility and Statistics 3");
arrList.add("999 Dota 2 Dota Guide 3");
System.out.println("Enter code to search");
int code = scan.next();
//Desired output
Enter code to search:
A29
A30
A29 CS 313 Digital Design 3
A30 IT 212 Discrete Structures 3
//
Run Code Online (Sandbox Code Playgroud)
您最好创建一个类并将该属性(如branch,rollno..etc)添加到该类,并将该类的对象添加到arrayList并进行迭代和比较以查找您正在查找的特定属性.现在很难搜索如此大的字符串和虽然看起来很糟糕.
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