仍在研究口齿不清的食谱和习语.
我有一个这样的列表:
((a b c) (d e f) nil (g h))
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我想将其合并到一个列表中,
(a b c d e f g h)
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似乎有一个单行班.
(apply #'append '((a b c) (d e f) (g h i)))
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要么
(loop for outer in '((a b c) (d e f) (g h i))
nconcing (loop for inner in outer collecting inner))
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