如何在flask-restful中自定义响应内容类型？

Question

我希望能够返回除application/json之外的东西,即kml.

我有以下内容:

@api.representation('application/vnd.google-earth.kml+xml')
def kml(data):
    return Response(data, mimetype='application/vnd.google-earth.kml+xml')

class mykml(restful.Resource):

    def get(self):
        r = requests.get("http://myurl/kml") # This retrieves a .kml file   
        response = make_response(r.content)
        response.headers['Content-Type'] = "application/vnd.google-earth.kml+xml"

        return response

为什么这仍然是返回的应用程序/ json？另外,如果我有不同的格式,我可以在没有装饰器的情况下动态更改类mykml中的respone的Content-Type吗？

进口: from flask import Flask, request, Response, session,make_response

Answer 1

如果您需要来自 API 方法的特定响应类型，则必须使用 Flask.make_response() 返回“预烘焙”响应对象：

def get(self):
    response = flask.make_response(something)
    response.headers['content-type'] = 'application/vnd.google-earth.kml'
    return response