dip*_*rus 4 python django redirect
我一直在使用Django的auth模块,但最近不得不关闭它.auth模块通过重定向到登录页面并将您从中注销的页面设置为?next=/currentPage参数来处理会话过期.
因此,如果我的会话到期,#dashboard我将被重定向到:
mydomain/account/login?next=/#dashboard
Run Code Online (Sandbox Code Playgroud)
离开Django auth模块后,我注意到这已经改为:
mydomain/account/login/#dashboard
Run Code Online (Sandbox Code Playgroud)
这看起来与我理解它在阅读URL Fragment和302重定向后应该起作用的方式一致,但是,我想操纵这个片段但是在我的HttpResponse对象中没有看到它.
django.contrib.auth使用以下函数来处理此请求,但我看不到它们移动片段的位置.实际上我只是想完全删除片段,但如果我不能,我会满足于将它放回?next=参数中.
def user_passes_test(test_func, login_url=None, redirect_field_name=REDIRECT_FIELD_NAME):
"""
Decorator for views that checks that the user passes the given test,
redirecting to the log-in page if necessary. The test should be a callable
that takes the user object and returns True if the user passes.
"""
def decorator(view_func):
@wraps(view_func, assigned=available_attrs(view_func))
def _wrapped_view(request, *args, **kwargs):
if test_func(request.user):
return view_func(request, *args, **kwargs)
path = request.build_absolute_uri()
# urlparse chokes on lazy objects in Python 3, force to str
resolved_login_url = force_str(
resolve_url(login_url or settings.LOGIN_URL))
# If the login url is the same scheme and net location then just
# use the path as the "next" url.
login_scheme, login_netloc = urlparse(resolved_login_url)[:2]
current_scheme, current_netloc = urlparse(path)[:2]
if ((not login_scheme or login_scheme == current_scheme) and
(not login_netloc or login_netloc == current_netloc)):
path = request.get_full_path()
from django.contrib.auth.views import redirect_to_login
return redirect_to_login(
path, resolved_login_url, redirect_field_name)
return _wrapped_view
return decorator
def login_required(function=None, redirect_field_name=REDIRECT_FIELD_NAME, login_url=None):
"""
Decorator for views that checks that the user is logged in, redirecting
to the log-in page if necessary.
"""
actual_decorator = user_passes_test(
lambda u: u.is_authenticated(),
login_url=login_url,
redirect_field_name=redirect_field_name
)
if function:
return actual_decorator(function)
return actual_decorator
Run Code Online (Sandbox Code Playgroud)
他们没有删除它.片段永远不会发送到后端:这就是浏览器的工作方式.
请注意,您的原始网址根本不会被解释next="/#dashboard",而是next="/"使用"信息中心"的后续片段.也就是说,片段与查询字符串是分开的,而不是它的一部分.
您需要做的是对哈希进行编码,使其成为查询字符串本身的一部分.
mydomain/account/login?next=/%23dashboard
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
814 次 |
| 最近记录: |