Wel*_*oud 2 mysql sql join count
我有2张桌子 - departments和employees.我想从中选择所有列,departments并且还添加一个列,其中包含每个部门中的子部门和员工数量.
简化表格如下所示:
departments:
id name parent_id
---------------------------------
1 IT NULL
2 HR NULL
3 Bussiness NULL
4 Web dev 1
5 Ecommerce 4
6 Advertisement 3
7 Control 3
8 Programmers 1
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employees:
id name department_id
---------------------------------
1 Adam 1
2 Ben 8
3 Charles 7
4 David 4
5 Eugen 4
6 Frank 6
7 Gustav 6
8 Heremy 4
9 Igor 5
10 Jacob 3
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我想要的结果是:
id name parent_id department_count employee_count
----------------------------------------------------------------------------
1 IT NULL 2 1
2 HR NULL 0 0
3 Bussiness NULL 2 1
4 Web dev 1 1 3
5 Ecommerce 4 0 1
6 Advertisement 3 0 2
7 Control 3 0 1
8 Programmers 1 0 1
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这是我的查询,但它无法正常工作.但是,如果我删除1 COUNT,那么数字是正确的.我认为NULL价值观是问题,但我不知道解决方案.
SELECT d.*, COUNT(d2.parent_id) AS department_count, COUNT(e.id) AS employee_count
FROM department AS d
LEFT JOIN department AS d2 ON (d.id = d2.parent_id)
LEFT JOIN employees AS z ON (e.department_id = d.id)
GROUP BY d.id
ORDER BY d.id
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欢迎对我的代码进行任何改进.
使用d2.id在不同的计数功能,所以对于一个部门重复孩子将只计算一次
SELECT d.*,
COUNT(distinct d2.id) AS department_count,
COUNT(distinct e.id) AS employee_count
FROM department AS d
LEFT JOIN department AS d2 ON (d.id = d2.parent_id)
LEFT JOIN employees AS e ON (e.department_id = d.id)
GROUP BY d.id
ORDER BY d.id
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