绘制带有一个角和两个切削刃的背景形状-Android

Question

我想绘制一个形状以将其设置为背景。形状具有一个角和两个切削刃。

这是我想要的形状的粗略图，其中有一个圆角和两个以直线连接的角。我正在使用并绘制它。你能帮上忙吗？

Answer 1

9补丁位图（根据UDI的回答）可能是最简单的，但是如果要在代码中进行操作，请创建一个自定义Shape：

import android.graphics.Canvas;
import android.graphics.Color;
import android.graphics.Paint;
import android.graphics.Path;
import android.graphics.drawable.shapes.Shape;
import android.graphics.RectF;

public class WeirdShape extends Shape {
    private static final int    COLOUR       = Color.RED;
    private static final float  STROKE_WIDTH = 1.0f;
    private static final float  CORNER = 10.0f;

    private final Paint border = new Paint();
    private final Path  path;  

    public WeirdShape() {
       path   = new Path();

        border.setColor      (COLOUR);
        border.setStyle      (Paint.Style.STROKE);
        border.setStrokeWidth(STROKE_WIDTH);
        border.setAntiAlias  (true);
        border.setDither     (true);
        border.setStrokeJoin (Paint.Join.ROUND);  
        border.setStrokeCap  (Paint.Cap.ROUND);  
    }

    @Override
    protected void onResize(float width, float height) {
        super.onResize(width, height);

        float dx = STROKE_WIDTH/2.0f;
        float dy = STROKE_WIDTH/2.0f;
        float x  = dx;
        float y  = dy;
        float w  = width  - dx;
        float h  = height - dy;

        RectF arc = new RectF(x,h-2*CORNER,x+2*CORNER,h);

        path.reset();
        path.moveTo(x + CORNER,y);
        path.lineTo(w - CORNER,y);
        path.lineTo(w,y + CORNER);
        path.lineTo(w, h);
        path.lineTo(x + CORNER,h);
        path.arcTo (arc,90.0f,90.0f);
        path.lineTo(dx,h - CORNER);
        path.lineTo(dx,y + CORNER);
        path.close();
    }

    @Override
    public void draw(Canvas canvas, Paint paint) {
       canvas.drawPath(path,border);
    }
}

然后在ShapeDrawable中使用自定义Shape作为背景Drawable：

view.setBackground(new ShapeDrawable(new WeirdShape()));

看起来像这样：