Django:OperationalError没有这样的表

Bri*_*ian 51 django django-cms

我正在使用Django-CMS的Django项目中构建一个相当简单的应用程序,研究.(这是我在项目/应用程序中的第一次尝试.)它的主要目的是存储各种知识资产(即研究人员撰写的文章,书籍等).

问题是,当我将浏览器指向/ research /时,我得到一个错误,表示'research_journal'表不存在("没有这样的表").

我正在使用带有sqlite3数据库的Djnago 1.6.5.

看python manage.py sql research收益率:

BEGIN;
CREATE TABLE "research_researchbase" (
    "id" integer NOT NULL PRIMARY KEY,
    "pub_date" datetime NOT NULL,
    "authors" varchar(200) NOT NULL,
    "year" varchar(25) NOT NULL,
    "title" varchar(200) NOT NULL,
    "subtitle" varchar(200) NOT NULL,
    "image_id" integer NOT NULL REFERENCES "filer_image" ("file_ptr_id"),
    "link" varchar(200) NOT NULL
)
;
CREATE TABLE "research_journal" (
    "researchbase_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "research_researchbase" ("id"),
    "journal" varchar(200) NOT NULL,
    "abstract" text NOT NULL,
    "citation" varchar(200) NOT NULL
)
;
CREATE TABLE "research_encyclopedia_chapter" (
    "researchbase_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "research_researchbase" ("id"),
    "encyclopedia" varchar(200) NOT NULL,
    "publisher" varchar(200) NOT NULL,
    "summary" varchar(200) NOT NULL
)
;
CREATE TABLE "research_book" (
    "researchbase_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "research_researchbase" ("id"),
    "publisher" varchar(200) NOT NULL,
    "summary" varchar(200) NOT NULL
)
;

COMMIT;
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我跑了python manage.py migrate research,得到:

/Users/XXX/Documents/repos/sfs/env/lib/python2.7/site-packages/app_data/fields.py:2: DeprecationWarning: django.utils.simplejson is deprecated; use json instead.
  from django.utils import simplejson as json

Running migrations for research:
- Nothing to migrate.
 - Loading initial data for research.
Installed 0 object(s) from 0 fixture(s)
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我跑了python manage.py syncdb并得到以下内容:

Syncing...
Creating tables ...
Installing custom SQL ...
Installing indexes ...
Installed 0 object(s) from 0 fixture(s)

Synced:
 > djangocms_admin_style
 > django.contrib.auth
 > django.contrib.contenttypes
 > django.contrib.sessions
 > django.contrib.admin
 > django.contrib.sites
 > django.contrib.sitemaps
 > django.contrib.staticfiles
 > django.contrib.messages
 > mptt
 > south
 > sekizai
 > django_select2
 > hvad

Not synced (use migrations):
 - djangocms_text_ckeditor
 - cms
 - menus
 - djangocms_style
 - djangocms_column
 - djangocms_file
 - djangocms_flash
 - djangocms_googlemap
 - djangocms_inherit
 - djangocms_link
 - djangocms_picture
 - djangocms_teaser
 - djangocms_video
 - reversion
 - polls
 - djangocms_polls
 - aldryn_blog
 - easy_thumbnails
 - filer
 - taggit
 - research
(use ./manage.py migrate to migrate these)
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这是models.py:

from django.db import models
from django.utils import timezone
from filer.fields.image import FilerImageField

import datetime

class ResearchBase(models.Model):
    pub_date = models.DateTimeField('date published')
    authors = models.CharField(max_length=200)
    year = models.CharField(max_length=25)
    title = models.CharField(max_length=200)
    subtitle = models.CharField(max_length=200, blank=True)
    image = FilerImageField()
    link = models.CharField(max_length=200, blank=True)

    def __unicode__(self):
        return self.title

    def was_published_recently(self):
        return self.pub_date >= timezone.now() - datetime.timedelta(days=1)


class Journal(ResearchBase):
    journal = models.CharField(max_length=200)
    abstract = models.TextField()
    citation = models.CharField(max_length=200)


class Encyclopedia_Chapter(ResearchBase):
    encyclopedia = models.CharField(max_length=200)
    publisher = models.CharField(max_length=200)
    summary = models.CharField(max_length=200)


class Book(ResearchBase):
    publisher = models.CharField(max_length=200)
    summary = models.CharField(max_length=200)
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这是我的views.py(注意我通过渲染传递了两个对象,忽略了我还没有在整个交易中包含类Book的事实):

from django.shortcuts import render, get_object_or_404
from django.http import HttpResponse, Http404
from django.template import RequestContext, loader

from research.models import Journal, Encyclopedia_Chapter, Book

def research_index(request):
    latest_journal_list = Journal.objects.order_by('-pub_date')[:5]
    latest_chapter_list = Encyclopedia_Chapter.objects.order_by('-pub_date')[:5]

    context = {
        'latest_journal_list': latest_journal_list,
        'latest_chapter_list': latest_chapter_list
    }

    return render(request, 'research/index.html', context)

def journal_detail(request, journal_id):
    journal = get_object_or_404(Journal, pk=journal_id)
    return render(request, 'research/journal_detail.html', {'journal': journal})

def chapter_detail(request, chapter_id):
    chapter = get_object_or_404(Encyclopedia_Chapter, pk=chapter_id)
    return render(request, 'research/chapter_detail.html', {'chapter': chapter})
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这是应用程序的url.py:

from django.conf.urls import patterns, url

from research import views

urlpatterns = patterns('',
    url(r'^$', views.research_index, name='research'),
    url(r'^(?P<journal_id>\d+)/$', views.journal_detail, name='journal_detail'),
    url(r'^(?P<chapter_id>\d+)/$', views.chapter_detail, name='chapter_detail'),
)
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这是index.html模板:

{% extends 'research/base.html' %}

{% block research_content %}

<div class="container">
    <div class="row featurette">
        <h3 id="research">Peer-reviewed Journal Articles</h3>
        {% if latest_journal_list %}
            <ul id="research">
            {% for journal in latest_journal_list %}
                <li id="research">
                            <img src="{{ journal.image.url }}" id="research">
                            <h4>{{ journal.journal }}</h4>
                            <h5>{{ journal.title }}</h5>
                            <a href="{% url 'research:journal_detail' journal.id %}">Read More</a>
                        </li>
            {% endfor %}
            </ul>
        {% else %}
            <p>No journals are available.</p>
        {% endif %}
    </div>

    <div class="row featurette">
        <h3 id="research">Encyclopedia Chapters</h3>
        {% if latest_chapter_list %}
            <ul id="research">
            {% for chapter in latest_chapter_list %}
                <li id="research">
                            <img src="{{ chapter.image.url }}" id="research">
                            <h4>{{ chapter.journal }}</h4>
                            <h5>{{ chapter.title }}</h5>
                            <a href="{% url 'research:chapter_detail' chapter.id %}">Read More</a>
                        </li>
            {% endfor %}
            </ul>
        {% else %}
            <p>No encyclopedia chapters are available.</p>
        {% endif %}
    </div>
</div>

{% endblock %}
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万一重要,这是我的cms_app.py:

from cms.app_base import CMSApp
from cms.apphook_pool import apphook_pool
from django.utils.translation import ugettext_lazy as _


class ResearchApp(CMSApp):
    name = _("Research App")
    urls = ["research.urls"]
    app_name = "research"

apphook_pool.register(ResearchApp)
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思考?任何帮助将不胜感激.

fif*_*nce 121

本页面的评论对我和其他一些人有用.它值得拥有自己的答案:

python manage.py migrate --run-syncdb
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  • 不要忘记先运行`python makemigrations` (5认同)
  • 我找到了它:` - run-syncdb` - >*为没有迁移的应用创建表.* (5认同)
  • 这行得通,但是在运行makemigrations和上面的命令之前,我必须从&lt;app_dir&gt; / migrations中删除.py和.pyc迁移文件。 (2认同)

Str*_*ker 26

对于django 1.10,您可能需要这样做python manage.py makemigrations appname.


Mic*_*rts 25

如果有人发现任何建议:

python manage.py makemigrations
python manage.py migrate
python manage.py migrate --run-syncdb
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失败,您可能需要migrations在应用程序目录中添加一个名为“ ”的文件夹,并创建一个空__init__.py文件。


Bri*_*ian 17

看起来我的迁移存在问题.

我跑了./manage.py schemamigration research --auto,发现很多字段都没有指定默认值.

所以,我./manage.py schemamigration research --init跟着跑了./manage.py migrate research

从那里重新运行服务器就可以了!

  • `manage.py migrate --run-syncdb`为我工作 (29认同)
  • 它说“未知命令:‘schemamigration’”。您指的是 showmigrations 吗? (3认同)

小智 6

当您尚未迁移到新创建的表时会出现此错误,因此,首先在 cmd 上写入命令为:python manage.py makemigrations然后编写另一个命令来应用由 makemigrations 命令进行的这些迁移:python manage.py migrate


Rav*_*ina 5

通过运行迁移可以解决此问题。

  1. python manage.py makemigrations
  2. python manage.py migrate

在中进行更改时,请执行以上操作models.py。


小智 5

运行以下命令为我解决了这个问题

  1. python manage.py migrate
  2. python manage.py makemigrations
  3. python manage.py makemigrations appName