Kyl*_*man 6 abaddressbook ios swift
我有一个用Swift编写的应用程序,它从他们的地址簿中提取用户联系人.
我想过滤掉只包含公司名称的联系人(这样你就可以得到"假定的"真人联系而不是商家)
以下是我在app的Objective-C版本中实现的方法:
NSArray *allContacts = (__bridge_transfer NSArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);
NSPredicate *predicate = [NSPredicate predicateWithBlock:^BOOL(id person, NSDictionary *bindings) {
NSString *firstName = CFBridgingRelease(ABRecordCopyValue((__bridge ABRecordRef)person, kABPersonFirstNameProperty));
NSString *lastName = CFBridgingRelease(ABRecordCopyValue((__bridge ABRecordRef)person, kABPersonLastNameProperty));
return (firstName || lastName);
}];
NSArray *peopleNotCompanies = [allContacts filteredArrayUsingPredicate:predicate];
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这很好用,所以这是我尝试在Swift中做到这一点:
var contactList: NSArray = ABAddressBookCopyArrayOfAllPeople(addressBook).takeRetainedValue()
var predicate: NSPredicate = NSPredicate { (AnyObject person, NSDictionary bindings) -> Bool in
var firstName: String = ABRecordCopyValue(person as ABRecordRef, kABPersonFirstNameProperty).takeRetainedValue() as String
var lastName: String = ABRecordCopyValue(person as ABRecordRef, kABPersonLastNameProperty).takeRetainedValue() as String
return firstName || lastName
})
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现在这有两个问题.我在return语句和谓词调用结束时收到这些错误:

如何在Swift中的ObjC代码中提供类似的功能?或者有更好的方法在swift中检查联系人是否只有公司名称,然后从最终数组中省略它?
谢谢!
如果firstName和lastName是可选字符串,则可以将它们与nil进行比较,并在布尔表达式中使用它们.
你的第二个错误是由于关闭后额外的paren.这段代码应该有效.
var predicate: NSPredicate = NSPredicate { (AnyObject person, NSDictionary bindings) -> Bool in
var firstName: String? = ABRecordCopyValue(person as ABRecordRef, kABPersonFirstNameProperty).takeRetainedValue() as? String
var lastName: String? = ABRecordCopyValue(person as ABRecordRef, kABPersonLastNameProperty).takeRetainedValue() as? String
return firstName != nil || lastName != nil
}
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小智 5
如果将NSArray转换为Swift数组,则可以使用Swift的Array.filter方法.为清晰起见,这是一个简单对象的示例:
let arrObjc: NSArray = ["aaa", "bab", "bbb", "baa", "cbc"]
let arr: [AnyObject] = arrObjc //create a swift array with same data
// filter takes a block that returns a boolean. True: keep the item, False: drop it.
arr.filter{
if let s = $0 as? String { // first try to cast AnyObject to our expected type.
return contains(s, "a") // return true if we want this item, false otherwise.
} else {
return false // this object is of the wrong type, return false.
}
}
// returns: ["aaa", "bab", "baa"]
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