Osc*_*ord 13 python sql sqlalchemy
我目前在以下方面有自我参照关系Foo:
parent_id = DB.Column(DB.Integer, DB.ForeignKey('foo.id'))
parent = DB.relation(
'Foo',
remote_side=[id],
backref=DB.backref(
'children',
primaryjoin=('and_(foo.c.id==foo.c.parent_id, foo.c.is_deleted==False)')
)
)
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现在我试图排除任何is_deleted设置为true的孩子.我很确定问题是它是在检查is_deleted父母,但我不知道从哪里开始.
如何修改关系以使子项is_deleted不包含在结果集中?
我尝试着回答这个问题。我的解决方案应该适用于 SQLAlchemy>=0.8。
实际上,这里发生的事情并不令人惊讶,但在使用此类模式时必须小心谨慎,因为身份映射的状态Session不会始终反映数据库的状态。
我使用post_update中的开关来relationship打破此设置所产生的循环依赖性。有关详细信息,请参阅有关此的 SQLAlchemy 文档。
警告:事实上,Session并不总是反映数据库的状态可能会导致严重的错误和其他混乱。在这个例子中,我用来expire_all显示数据库的真实状态,但这不是一个好的解决方案,因为它重新加载所有对象并且所有未flush更改的更改都会丢失。使用expire并expire_all小心!
#!/usr/bin/env python
import sqlalchemy as sa
import sqlalchemy.orm as orm
from sqlalchemy.ext.declarative import declarative_base
engine = sa.create_engine('sqlite:///blah.db')
Base = declarative_base()
Base.bind = engine
class Obj(Base):
__table__ = sa.Table(
'objs', Base.metadata,
sa.Column('id', sa.Integer, primary_key=True),
sa.Column('parent_id', sa.Integer, sa.ForeignKey('objs.id')),
sa.Column('deleted', sa.Boolean),
)
# I used the remote() annotation function to make the whole thing more
# explicit and readable.
children = orm.relationship(
'Obj',
primaryjoin=sa.and_(
orm.remote(__table__.c.parent_id) == __table__.c.id,
orm.remote(__table__.c.deleted) == False,
),
backref=orm.backref('parent',
remote_side=[__table__.c.id]),
# This breaks the cyclical dependency which arises from my setup.
# For more information see: http://stackoverflow.com/a/18284518/15274
post_update=True,
)
def __repr__(self):
return "<Obj id=%d children=%d>" % (self.id, len(self.children))
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def main():
session = orm.sessionmaker(bind=engine)
db = session()
Base.metadata.create_all(engine)
p1 = Obj()
db.add(p1)
db.flush()
p2 = Obj()
p2.deleted = True
p1.children.append(p2)
db.flush()
# prints <Obj id=1 children=1>
# This means the object is in the `children` collection, even though
# it is deleted. If you want to prevent this you may want to use
# custom collection classes (not for novices!).
print p1
# We let SQLalchemy forget everything and fetch the state from the DB.
db.expire_all()
p3 = db.query(Obj).first()
# prints <Obj id=1 children=0>
# This indicates that the children which is still linked is not
# loaded into the relationship, which is what we wanted.
print p3
db.rollback()
if __name__ == '__main__':
main()
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