PDO对单个字符串的多个表列运行LIKE查询

Siz*_*ode 0 php mysql pdo

我现在想在表的两列上使用like。

表名= roomnames

表列= roomIDroomNameroomNo

我有一个输入字段,该字段发送一个应该在其上执行查询的字符串值。

以下是PHP PDO代码

<?php
/**
 * Created by PhpStorm.
 * User: HaiderHassan
 * Date: 9/3/14
 * Time: 9:52 PM
 */
header('Access-Control-Allow-Origin: *');
try {
    $conn = new PDO('mysql:host=localhost;dbname=houserentsystem;charset=utf8', 'root', 'admin');
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch(PDOException $e) {
    echo 'ERROR: ' . $e->getMessage();
}
if($_POST['searchFilter']){
    $searchFilter = $_POST['searchFilter'];
    $stmt = $conn->prepare("SELECT roomName, roomNo FROM roomnames WHERE roomName LIKE ? OR roomNo LIKE ?");
    $stmt->execute(array('%'.$searchFilter.'%'));
    $results = $stmt->fetchAll(PDO::FETCH_ASSOC);
    $stmt->closeCursor();
    print_r(json_encode($results));
}
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我尝试的查询是错误的,不能在这里工作是我现在尝试的。

$stmt = $conn->prepare("SELECT roomName, roomNo FROM roomnames WHERE roomName LIKE ? OR roomNo LIKE ?");
$stmt->execute(array('%'.$searchFilter.'%'));
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我想搜索房间号或房间名称,如果数据库表中存在该房间号或房间名称,它将显示结果。

对不起,我的英语不好。我希望我已经解释了。我想在多列中搜索针对输入字符串的表,输入字符串可以是no或name。数字代表房间编号,名字代表房间名称。

VMa*_*Mai 5

您必须为每个参数都有一个值,因此,请在参数值数组中将您的searchfilter加倍:

$stmt = $conn->prepare("SELECT roomName, roomNo FROM roomnames WHERE roomName LIKE ? OR roomNo LIKE ?");
$stmt->execute(array('%'.$searchFilter.'%','%'.$searchFilter.'%' ));
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