PHP:如何检查日期是今天,昨天还是明天

Question

我想检查,如果日期是今天,明天,昨天或其他.但我的代码不起作用.

码:

$timestamp = "2014.09.02T13:34";
$date = date("d.m.Y H:i");
$match_date = date('d.m.Y H:i', strtotime($timestamp));

if($date == $match_date) { 

    //Today

} elseif(strtotime("-1 day", $date) == $match_date) {

    //Yesterday

} elseif(strtotime("+1 day", $date) == $match_date) {

    //Tomorrow

} else {

    //Sometime

}

代码总是在其他情况下.

Answer 1

第一.您在使用函数时遇到错误,strtotime请参阅PHP文档

int strtotime ( string $time [, int $now = time() ] )

您需要修改代码以将整数时间戳传递到此函数中.

第二.您使用格式dmY H:i包括时间部分.如果你只想比较日期,你必须删除时间部分,例如`$ date = date("dmY");``

第三.我不确定它是否以相同的方式为您工作,但我的PHP不理解日期格式$timestamp并返回01.01.1970 02:00进入$match_date

$timestamp = "2014.09.02T13:34";
date('d.m.Y H:i', strtotime($timestamp)) === "01.01.1970 02:00";

您需要检查是否strtotime($timestamp)返回正确的日期字符串.如果不是,则需要指定$timestamp变量中使用的格式.您可以使用函数之一date_parse_from_format或DateTime :: createFromFormat来完成此操作

这是一个工作示例:

$timestamp = "2014.09.02T13:34";

$today = new DateTime(); // This object represents current date/time
$today->setTime( 0, 0, 0 ); // reset time part, to prevent partial comparison

$match_date = DateTime::createFromFormat( "Y.m.d\\TH:i", $timestamp );
$match_date->setTime( 0, 0, 0 ); // reset time part, to prevent partial comparison

$diff = $today->diff( $match_date );
$diffDays = (integer)$diff->format( "%R%a" ); // Extract days count in interval

switch( $diffDays ) {
    case 0:
        echo "//Today";
        break;
    case -1:
        echo "//Yesterday";
        break;
    case +1:
        echo "//Tomorrow";
        break;
    default:
        echo "//Sometime";
}

Answer 2

<?php 
 $current = strtotime(date("Y-m-d"));
 $date    = strtotime("2014-09-05");

 $datediff = $date - $current;
 $difference = floor($datediff/(60*60*24));
 if($difference==0)
 {
    echo 'today';
 }
 else if($difference > 1)
 {
    echo 'Future Date';
 }
 else if($difference > 0)
 {
    echo 'tomorrow';
 }
 else if($difference < -1)
 {
    echo 'Long Back';
 }
 else
 {
    echo 'yesterday';
 }  
?>

Answer 3

我想这会对你有所帮助:

<?php
$date = new DateTime();
$match_date = new DateTime($timestamp);
$interval = $date->diff($match_date);

if($interval->days == 0) {

    //Today

} elseif($interval->days == 1) {
    if($interval->invert == 0) {
        //Yesterday
    } else {
        //Tomorrow
    }
} else {
    //Sometime
}

Answer 4

今天/昨天/明天的简单单行：

$someDate = '2021-11-07'; // date in any format

$isToday = date('Ymd') == date('Ymd', strtotime($someDate));
$isYesterday = date('Ymd') == date('Ymd', strtotime($someDate) + 86400);
$isTomorrow = date('Ymd') == date('Ymd', strtotime($someDate) - 86400);

Answer 5

在Php(shame ^^)中没有内置函数可以做到这一点.您想要将日期字符串与今天进行比较,您可以使用简单的方法substr来实现它:

if (substr($timestamp, 0, 10) === date('Y.m.d')) { today }
elseif (substr($timestamp, 0, 10) === date('Y.m.d', strtotime('-1 day')) { yesterday }

没有日期转换,简单.

Answer 6

function getRangeDateString($timestamp) {
    if ($timestamp) {
        $currentTime=strtotime('today');
        // Reset time to 00:00:00
        $timestamp=strtotime(date('Y-m-d 00:00:00',$timestamp));
        $days=round(($timestamp-$currentTime)/86400);
        switch($days) {
            case '0';
                return 'Today';
                break;
            case '-1';
                return 'Yesterday';
                break;
            case '-2';
                return 'Day before yesterday';
                break;
            case '1';
                return 'Tomorrow';
                break;
            case '2';
                return 'Day after tomorrow';
                break;
            default:
                if ($days > 0) {
                    return 'In '.$days.' days';
                } else {
                    return ($days*-1).' days ago';
                }
                break;
        }
    }
}