3 javascript cloud push-notification parse-platform
我正在写一个关于parse.com的javascript云代码SDK的脚本.以下是我在parse.com帐户中保存的信息以及我要对其进行的操作.
我在一个名为TestItem的解析类中保存了一堆项目,这些项目有一个objectId,项目名称,用餐时间(午餐,晚餐)以及列的位置.我还有一个名为UserFavourites的课程.在此类中,对象具有objectId,项目名称和指向将项目保存为收藏夹的用户的指针.
有了这些信息,我试图用javascript编写一个云代码脚本.这将使项目与用户喜欢的项目相匹配,并向他们发送推送通知,说明项目的位置和内容以及项目的位置.我有一些代码可以做到这一点,但是这段代码会为每个项目发送一个不同的通知,这可能会让用户烦恼,这就是代码.
Parse.Cloud.define("push", function(request, response) {
var TestItem = Parse.Object.extend("TestItem");
var query = new Parse.Query(TestItem);
query.limit(1000);
query.equalTo('school', 'Union College (NY)');
query.find({
success: function(resultsItem) {
//console.log("Successfully retrieved " + resultsItem.length + " :1111.");
for (var i = 0; i < resultsItem.length; i++) {
var object = resultsItem[i];
var item = object.get('item');
var school = object.get('school');
var meal = object.get('meal');
var meal = meal.toLowerCase();
var diningLocation = object.get('schoolMenu');
//var itemArray = [];
var UserFavourite = Parse.Object.extend("UserFavourite");
var queryFavourite = new Parse.Query(UserFavourite);
queryFavourite.limit(1000);
queryFavourite.equalTo("item", item)
queryFavourite.equalTo("school", school)
queryFavourite.find({
success: function(results) {
for (var i = 0; i < results.length; i++) {
var objectFav = results[i];
var user = objectFav.get('user');
var userID = user.id;
var realItem = objectFav.get('item');
console.log(objectFav.get('user'));
console.log(objectFav.get('item'));
var UserClass = Parse.Object.extend("User");
var queryUser = new Parse.Query(UserClass);
queryUser.get(userID, {
success: function(userResult) {
console.log(userResult.get('school'));
console.log('install:' + userResult.get('installation').id);
var userInstallationId = userResult.get('installation').id;
var queryInstallation = new Parse.Query(Parse.Installation);
queryInstallation.equalTo('objectId', userInstallationId);
queryInstallation.find({
success: function(results) {
console.log('number' + results.length);
Parse.Push.send({
// deviceType: [ "ios" ],
where: queryInstallation,
data: {
alert: realItem + " is being served at " + diningLocation + " for " + meal
}
},
{
success: function() {
// Push was successful
},
error: function(error) {
// Handle error
}
});
},
error: function(error) {
console.log('error');
}
});
},
error: function(error) {
console.log('error');
}
});
}
},
error: function(error) {
alert("Error: " + error.code + " " + error.message);
}
});
}
},
error: function(error) {
alert("Error: " + error.code + " " + error.message);
}
});
});
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正如你所看到的那样它很长而且看起来不太好看,我试图将项目保存到数组中,以避免发送两个或更多通知但无法使其工作.
所以我开始编写另一个使用promises的脚本,它看起来更好但是现在还没有得到它,它可以将项目与有优势项目的用户匹配,并将这些用户的objectId放在一个数组中.这是代码.
Parse.Cloud.define("test", function(request, response) {
var UserFavourite = Parse.Object.extend("UserFavourite");
var queryFavourite = new Parse.Query(UserFavourite);
var userArray = [];
var TestItem = Parse.Object.extend("TestItem");
var query = new Parse.Query(TestItem);
query.limit(1000);
query.equalTo('school', 'Union College (NY)');
query.find().then(function(results) {
return results;
}).then(function(results) {
var promises = [];
for (var i = 0; i < results.length; i++) {
var object = results[i];
var item = object.get('item');
var school = object.get('school');
var meal = object.get('meal');
var UserFavourite = Parse.Object.extend("UserFavourite");
var queryUser = new Parse.Query(UserFavourite);
queryUser.equalTo("item", item);
queryUser.equalTo("school", school);
var prom = queryUser.find().then(function(users) {
for (var i = 0; i < users.length; i++) {
var user = users[i];
var userID = user.get('user').id;
if (userArray.indexOf(userID) === -1) {
userArray.push(userID);
}
}
return userArray;
});
promises.push(prom);
}
return Parse.Promise.when.apply(Parse.Promise, promises);
}).then(function(results) {
console.log(userArray);
});
});
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但是现在有了这段代码,我不知道去哪里,我认为使用promises,这是正确的方法,但我现在感到困惑,因为一旦我拥有一个项目有利于做什么的所有用户,我需要为了获得那些受欢迎且在TestItem类中可用的项目,这是我正在努力的地方.
这是我的UserFavourite类的图片,它有一个指向可以看到的收藏项目的用户的指针,并且用户也有多个收藏夹.

感谢一大堆提前帮助.
这是你的代码,我改变了一些东西.
Parse.Cloud.define("getAllFavoriteItems", function (request, response) {
var TestItems = Parse.Object.extend("TestItems");
var UserFavorites = Parse.Object.extend("UserFavorites");
var testItemsQuery = new Parse.Query(TestItems);
var userFavoritesQuery = new Parse.Query(UserFavorites);
testItemsQuery.equalTo('school', 'Union College (NY)');
userFavoritesQuery.include('testItems'); //This makes sure to pull all of the favorite item data instead of just the pointer object
userFavoritesQuery.matchesQuery('testItem', testItemsQuery); //This will run this second query against the TestItems
userFavoritesQuery.limit(1000); //limit results to 1000
userFavoritesQuery.ascending('userId'); //group the user id's together in your array
userFavoritesQuery.find({
success:function(results) {
var pushNotificationMessage = "";
var userId = "";
for (var i=0; i <results.length; i++) {
if (results[i].get('userId') != userId) {
if (results[i].get('userId') != "") {
//TODO send push notification
}
userId = results[i].get('userId');
pushNotificationMessage = ""; //start a new push notification
}
pushNotificationMessage += results[i].get('item').get('name') + ": " + results[i].get('item').get('location') + "\n";
//SOMEWHERE BEFORE HERE I NEED THE INSTALLATION ID OF THE USER
//TO SEND THE PUSH TO THAT USER
Parse.Push.send({
// deviceType: [ "ios" ],
where: queryInstallation,
data: {
alert: pushNotificationMessage
}
},
{
success: function() {
// Push was successful
},
error: function(error) {
// Handle error
}
});
}
response.success(true);
},
error:function(error) {
response.error();
}
})
});
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一些代码可能会为每个用户创建推送,但粗略的轮廓
if (i > 0) {
if (results[i].get('user') === results[i-1].get('user')) {
userItems.push(results[i]);
}
else {
userItems.length = 0;
}
}
else {
userItems.push(results[i]);
}
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如果你明白我要做什么,不知道让我知道......
因此,用户有两个受欢迎的项目我希望它将其分组为一个短语,该短语说明两个项目的服务内容和位置
这是发送推送的代码
Parse.Push.send({
// deviceType: [ "ios" ],
where: queryInstallation,
data: {
alert: pushNotificationMessage
}
},
{
success: function() {
// Push was successful
},
error: function(error) {
// Handle error
}
});
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它也可以用then/promises完成,

我同意@Maxwell你的UserFavorite应该有User和TestItem的链接.这使得您的云功能变得如此简单:
Parse.Cloud.define("getAllFavoriteItems", function(request, response) {
var TestItem = Parse.Object.extend("TestItem");
var UserFavorites = Parse.Object.extend("UserFavorites");
var testItemsQuery = new Parse.Query(TestItem);
var userFavoritesQuery = new Parse.Query(UserFavorites);
testItemsQuery.equalTo('school', request.params.school);
userFavoritesQuery.include('testItem');
userFavoritesQuery.include('user');
userFavoritesQuery.matchesQuery('testItem', testItemsQuery); //This will run this second query against the TestItems
userFavoritesQuery.find().then(function(results) {
var alerts = {};
for(var i =0 ; i<results.length; i++ ){
var user = results[i].get('user');
var testItem = results[i].get('testItem');
if(user && testItem){
var instId = user.get('installationId');
if(!alerts[instId]) {
alerts[instId] = [];
}
var m = results[i].get('item') + " is being served at {{diningLocation}} for " + testItem.get('meal');
alerts[instId].push(m);
}
}
response.success(alerts);
}, function(error) {
response.error();
});
});
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这是您可以在我的github仓库中找到的工作代码.您还可以在此处查看工作演示
这个想法与Maxwell的答案相同:在UserFavorites类中链接到User(两者都是instalId)和TestItem实体.我刚刚通过在查询中包含user和testItems属性来使它工作,所以当返回的结果按学校名称过滤时,我已经有了一个installationIds列表.这是我的架构:
用户

测试项目

UserFavorites

在此代码中,我添加了推送通知:
Parse.Cloud.define("getAllFavoriteItems", function(request, response) {
var TestItem = Parse.Object.extend("TestItem");
var UserFavorites = Parse.Object.extend("UserFavorites");
var testItemsQuery = new Parse.Query(TestItem);
var userFavoritesQuery = new Parse.Query(UserFavorites);
testItemsQuery.equalTo('school', request.params.school);
function SendPush(installationId, msg) {
var query = new Parse.Query(Parse.Installation);
query.equalTo('objectId', installationId);
Parse.Push.send({
where: query,
data: {alert: msg}
});
}
userFavoritesQuery.include('testItem');
userFavoritesQuery.include('user');
userFavoritesQuery.matchesQuery('testItem', testItemsQuery); //This will run this second query against the TestItems
userFavoritesQuery.find().then(function(results) {
var groupedAlerts = {};
// manually iterating though results to get alert strings ang group by user in groupedAlerts[installationId]
for(var i =0 ; i<results.length; i++ ){
var user = results[i].get('user');
var testItem = results[i].get('testItem');
if(user && testItem){
var instId = user.get('installationId');
if(!groupedAlerts[instId]) {
groupedAlerts[instId] = [];
}
var m = results[i].get('item') + " is being served at {{dining Location}} for " + testItem.get('meal');
groupedAlerts[instId].push(m);
}
}
// reformat to array and send push notifications
var alerts = [];
for(var key in groupedAlerts) {
alerts.push({
installationId: key,
alerts: groupedAlerts[key],
});
// Send push notifications
SendPush(key, groupedAlerts[key].join());
}
response.success(alerts);
}, function(error) {
response.error();
});
});
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我还在现场演示中更新了测试数据(只需按下Get Alerts)或者随意使用测试数据来更改云代码响应.gitnub repo也是最新的.
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