从熊猫中的元组到多个列

Question

如何转换此数据帧

                                          location  value                       
0                   (Richmond, Virginia, nan, USA)    100                       
1              (New York City, New York, nan, USA)    200                       

对此:

    city            state       region    country   value
0   Richmond        Virginia    nan       USA       100
1   New York City   New York    nan       USA       200

请注意,location第一个数据框中的列包含元组.我想在列中创建四列location.

Answer 1

new_col_list = ['city','state','regions','country']
for n,col in enumerate(new_col_list):
    df[col] = df['location'].apply(lambda location: location[n])

df = df.drop('location',axis=1)

Answer 2

如果返回一系列(拆分)位置,则可以直接将结果DF与值列合并(join以合并索引).

addr = ['city', 'state', 'region', 'country']
df[['value']].join(df.location.apply(lambda loc: Series(loc, index=addr)))

   value           city     state  region country
0    100       Richmond  Virginia     NaN     USA
1    200  New York City  New York     NaN     USA