Ben*_*tch 4 c# regex linq list
这是我想要做的但没有成功.我想打电话from x in list1和join y in list2 where regex.Match(x.Value).Success.完成这些步骤后,我需要打String.Replace两次电话x.Value.然后调用on和select运算符.我希望它看起来像第二个例子.如何实现这一目标?
这是我的列表的样子:
list1 list2
Name Value Name Value
item.1 $(prod1) prod1 prodVal1
item.2 $(prod2) prod2 prodVal2
item.3 prod3 prod3 prodVal3
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这是我的列表应该是这样的:
updatedList
Name Value
item.1 prodVal1
item.2 prodVal2
item.3 prod3
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示例1(这是我目前拥有的):
foreach (var x in list1)
{
Match match = reg.Match(x.Value);
if (match.Success)
{
x.Value = x.Value.Replace("$(", "");
x.Value = x.Value.Replace(")", "");
}
}
var commonItems = from x in list1
join y in list2
on x.Value equals y.Name
//where regex.Match(x.Value).Success
select new { Item = x, NewValue = y.Value };
foreach (var x in commonItems)
{
x.Item.Value = x.NewValue;
}
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例2:
var commonItems = from x in list1
join y in list2
where regex.Match(x.Value).Success
//do x.Value.Replace("$(", "")
//do x.Value.Replace(")", "")
//then call
on x.Value equals y.Name
select new { Item = x, NewValue = y.Value };
foreach (var x in commonItems)
{
x.Item.Value = x.NewValue;
}
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如果我正确理解了您想要let在查询中使用的内容:
var commonItems = from x in list1
join y in list2
let newX = x.Value.Replace("$(", "").Replace(")", "")
where regex.Match(x.Value).Success
&& newX == y.Name
select new { Item = newX, NewValue = y.Value };
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你确定你需要Regex.Match吗?你可以在不使用它的情况下获得相同的结果,无论如何我添加了两个版本......
在 1\xc2\xb0 版本中,您可以使用简单的 If 语句来检查值是否已更改
\n\nNewValue = x.Value != x1 ? y.Value: x.Value \nRun Code Online (Sandbox Code Playgroud)\n\n示例代码
\n\n给定这个类
\n\nclass MyClass\n{\n public string Name { get; set; }\n public string Value { get; set; }\n}\nRun Code Online (Sandbox Code Playgroud)\n\n。
\n\n添加项目
\n\n var list1 = new List<MyClass>();\n list1.Add(new MyClass { Name = "item.1", Value = "$(prod1)" } );\n list1.Add(new MyClass { Name = "item.2", Value = "$(prod2)" });\n list1.Add(new MyClass { Name = "item.3", Value = "prod3" });\n\n var list2 = new List<MyClass>();\n list2.Add(new MyClass { Name = "prod1", Value = "prodVal1" });\n list2.Add(new MyClass { Name = "prod2", Value = "prodVal2" });\n list2.Add(new MyClass { Name = "prod3", Value = "prodVal3" });\nRun Code Online (Sandbox Code Playgroud)\n\n获取常用列表
\n\n var q = from x in list1\n let x1 = x.Value.Replace("$(", "").Replace(")", "")\n join y in list2 on x1 equals y.Name\n select new { \n Item = x.Name, \n NewValue = x.Value != x1 ? y.Value: x.Value \n };\n\n\n foreach (var s in q)\n {\n Console.WriteLine(s.Item + " " + s.NewValue);\n }\nRun Code Online (Sandbox Code Playgroud)\n\n结果
\n\nitem.1 prodVal1\nitem.2 prodVal2\nitem.3 prod3\nRun Code Online (Sandbox Code Playgroud)\n\nPS:我认为你不需要Regex,但以防万一这个版本可以使用它。
var q = from x in list1\n let x1 = x.Value.Replace("$(", "").Replace(")", "")\n join y in list2 on x1 equals y.Name\n select new\n {\n Item = x.Name,\n NewValue = Regex.Match(x.Value, x1).Success ? x.Value : y.Value\n };\nRun Code Online (Sandbox Code Playgroud)\n