如何apply()从Scala.js代码调用Javascript对象上定义的函数?
显而易见的解决方案不起作用,因为applyScala.JS(?)总是将其编译到其父对象的函数调用中:
var test = {
apply: function(idx) {...},
apple: function(idx) {...}
}
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trait Test extends js.Object {
def apple(idx: Int) : Int = ???
def apply(idx: Int) : Int = ???
}
val test = js.Dynamic.global.test.asInstanceOf[Test]
test.apple(1) // works, of course
test.apply(1) // does not work (seems to be compiled into the call test(1) ?)
js.Dynamic.global.test.apply(1) // does not work either
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您可以使用apply外观类型注释方法@JSName("apply").这将产生所需的行为:
trait Test extends js.Object {
def apple(idx: Int) : Int = ???
@JSName("apply")
def apply(idx: Int) : Int = ???
}
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测试:
val test = js.Dynamic.literal(
apply = (idx: Int) => idx,
apple = (idx: Int) => idx
).asInstanceOf[Test]
test.apple(1) // -> 1
test.apply(1) // -> 1
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对于动态类型的情况,您必须applyDynamicNamed手动调用:
val dyn = test.asInstanceOf[js.Dynamic]
dyn.applyDynamicNamed("apply")(1) // -> 1
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