PHP If-Else-Finally

Question

我正在寻找更聪明的方法来解决我所谓的if-else-finally案例.

案例
根据不同的条件,对象的属性需要不同的值.仅当此属性已更改时,才会将对象保留为DB.

示例(伪代码)

if _condition-A_ then
    set object.property to value-A
else if _condition-B_ then
    set object.property to value-B
else if _condition-C_ then
    set object.property to value-C
finally
    object.persist()

我的解决方案

$changed = false;
if ($conditionA) {
    $changed = true;
    $this->property = 'A';
} elseif ($conditionB) {
    $changed = true;
    $this->property = 'B';
} elseif ($conditionC) {
    $changed = true;
    $this->property = 'C';
}
if ($changed) {
    $this->save();
}

有没有更好/更智能的解决方案呢？该switch-case-default构造是不可能的,因为条件是由每个if陈述中不同的较小的部分条件组合而成的.

Answer 1

你可以$changed = true;通过这种方式避免重复:

$changed = true;
if ($conditionA) {
    $this->property = 'A';
} elseif ($conditionB) {
    $this->property = 'B';
} elseif ($conditionC) {
    $this->property = 'C';
} else {
    $changed = false;
}
if ($changed) {
    $this->save();
}