如何从C#中的XmlNode获取参数值

Question

如何获取XmlNode标记中的参数值.例如:

<weather time-layout="k-p24h-n7-1">
    <name>Weather Type, Coverage, and Intensity</name>
    <weather-conditions weather-summary="Mostly Sunny"/>
</weather>

我想在节点'weather-conditions'中获取参数'weather-summary'的值.

Answer 1

var node = xmldoc.SelectSingleNode("weather/weather-conditions");
var attr = node.Attributes["weather-summary"];