打印双变量内容

Question

我尝试了以下代码片段,输出令我惊讶:

#include <stdio.h>
#include <math.h>

int main()
{
            double num;
            unsigned char ch;

            ch = 19;
            num = 1.0E+20 ;
            num += ch * 1.0E+18;
            printf("E18 = %lf \n",num);
            printf("E18 = %e \n",num);

            num = 11.0E+21 ;
            num += ch * 1.0E+19;
            printf("E19 = %lf <------\n",num);
            printf("E19 = %e <------\n",num);

            num = 11.0E+22 ;
            num += ch * 1.0E+20;
            printf("E20 = %lf\n",num);
            printf("E20 = %e\n",num);

            num = 11.0E+23 ;
            num += ch * 1.0E+21;
            printf("E21 = %lf\n",num);
            printf("E21 = %e\n",num);

            num = 11.0E+24 ;
            num += ch * 1.0E+22;
            printf("E22 = %lf <------\n",num);
            printf("E22 = %e <------\n",num);
    return 0;
}

该计划的输出:

E18 = 119000000000000000000.000000 
E18 = 1.190000e+20 
E19 = 11190000000000000524288.000000 <------
E19 = 1.119000e+22 <------
E20 = 111900000000000001048576.000000
E20 = 1.119000e+23
E21 = 1119000000000000044040192.000000
E21 = 1.119000e+24
E22 = 11189999999999999366660096.000000 <------
E22 = 1.119000e+25 <------

为什么数据在指数形式下打印时损坏了OK

Answer 1

因为,当数字变得足够大时,你会失去精确度:http://en.wikipedia.org/wiki/Floating_point