Raj*_*wat 5 php phpunit unit-testing constraints laravel
我是 Laravel 模型单元测试的新手。所以请看看并建议我做错了什么。我的代码如下。我有 2 个模型 User 和 UserState。
模型用户
public function state()
{
return $this->hasOne('UserState');
}
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模型用户状态
public function user()
{
return $this->belongsTo('User');
}
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现在我正在为 UserState 编写单元测试。下面给出:
单元测试 UserStateModelTest
public function testUserRelationIsTrue(){
$user = new User();
$user->username = 'testusername';
$user->save();
$this->assertEquals($user->user_id, $user->state->id);
}
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在 phpunit 测试运行期间,它生成错误
Illuminate\Database\QueryException: SQLSTATE[23000]: Integrity constraint violation:
1452 Cannot add or update a child row: a foreign key constraint fails
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如果你真的想测试一个关系方法,你甚至可以在不将模型保存到数据库的情况下进行。您仍然需要使用 RefreshDatabase trait(或 DatabaseMigrations trait),否则模型将不会映射到任何表。
# tests/Unit/ParentTest.php
/**
* Test Parent has HasMany relationship with Child model
* @test
*/
public function has_many_children_with_parent_id_fk()
{
$parent = new Parent;
$foreign_key = 'parent_id';
// Get the relationship object, not the data collection
$relationship = $parent->children();
$related_model = $relationship->getRelated();
// Assert this is a HasMany relationship
$this->assertInstanceOf(HasMany::class, $relationship);
// Assert the related model is Child
$this->assertInstanceOf(Child::class, $related_model);
// Assert the foreign key is the one we specified
// (This can be useful if you do not use the default one)
$this->assertEquals($foreign_key, $relationship->getForeignKeyName());
// Assert the foreign key is a column
// of the database table mapped by the Child model
$this->assertTrue(Schema::hasColumns($related_model->getTable(), array($foreign_key)));
}
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# tests/Unit/ChildTest.php
/**
* Test Child has belongsTo relationship with Parent model
* @test
*/
public function belongs_to_parent_with_parent_id_fk()
{
$child = new Child;
$foreign_key = 'parent_id';
// Get the relationship object, not the data collection
$relationship = $child->parent();
$related_model = $relationship->getRelated();
// Assert this is a BelongsTo relationship
$this->assertInstanceOf(BelongsTo::class, $relationship);
// Assert the related model is Parent
$this->assertInstanceOf(Parent::class, $related_model);
// Assert the foreign key is the one we specified
// (This can be useful if you do not use the default one)
$this->assertEquals($foreign_key, $relationship->getForeignKeyName());
// Assert the foreign key is a column
// of the database table mapped by the Child model
$this->assertTrue(Schema::hasColumns($relationship->getParent()->getTable(), array($foreign_key)));
}
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这有点少,但您可以创建自定义断言以将所有这些封装在 TestCase 所有测试文件扩展中。以下方法适合我的需要
# tests/TestCase.php
public function assertHasManyUsing($related_model, $relationship, $foreign_key)
{
$this->assertInstanceOf(HasMany::class, $relationship);
$this->assertInstanceOf($related_model, $relationship->getRelated());
$this->assertEquals($foreign_key, $relationship->getForeignKeyName());
$this->assertTrue(Schema::hasColumns($relationship->getRelated()->getTable(), array($foreign_key)));
}
public function assertBelongsToUsing($related_model, $relationship, $foreign_key)
{
$this->assertInstanceOf(BelongsTo::class, $relationship);
$this->assertInstanceOf($related_model, $relationship->getRelated());
$this->assertEquals($foreign_key, $relationship->getForeignKeyName());
$this->assertTrue(Schema::hasColumns($relationship->getParent()->getTable(), array($foreign_key)));
}
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现在,重构测试看起来像这样
# tests/Unit/ParentTest.php
/**
* Test Parent has HasMany relationship with Child model
* @test
*/
public function has_many_children_with_parent_id_fk()
{
$parent = new Parent;
$this->assertHasManyUsing(Child::class, $parent->children(), 'parent_id');
}
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# tests/Unit/ChildTest.php
/**
* Test Child has belongsTo relationship with Parent model
* @test
*/
public function belongs_to_parent_with_parent_id_fk()
{
$child = new Child;
$this->assertBelongsToUsing(Parent::class, $child->parent(), 'parent_id');
}
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