Python - 解析一个字符串并将其转换为列表

Pyt*_*ast 3 python string parsing list

我有一个字符串

a = "sequence=1,2,3,4&counter=3,4,5,6"
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如何将其转换为列表,即

sequence = [1,2,3,4]
counter = [3,4,5,6]
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fal*_*tru 12

使用urlparse.parse_qs(urllib.parse.parse_qs在Python 3.x中)解析查询字符串:

>>> import urlparse
>>> a = "sequence=1,2,3,4&counter=3,4,5,6"
>>> {key: [int(x) for x in value[0].split(',')]
...  for key, value in urlparse.parse_qs(a).items()}
{'counter': [3, 4, 5, 6], 'sequence': [1, 2, 3, 4]}
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