Sie*_*rox 3 java android input listener libgdx
我想在InputListener中使用exit()方法来查看光标是否在按钮内.
以下是libGDX文档中的解释.
public void exit(InputEvent event, float x, float y, int pointer, Actor toActor)
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每当鼠标光标或手指触摸移出演员时调用.
但是当我将光标放在按钮上然后将其移到按钮外时,不会调用该方法.我正在测试它System.out.println("exited");,我在控制台中什么都没得到.
编辑:
LibGDX版本:最新稳定的夜莺
InputListener实现:
//This button class is a custom class to make button creation easier. This is the constructor.
public Button(Vector2 position, String packLocation, String text, Stage stage, BitmapFont font, Color color) {
//Removed buttonStyle creation etc. to shorten the code.
button = new TextButton(text, buttonStyle);
button.setPosition(position.x, position.y);
stage.addActor(button);
Gdx.input.setInputProcessor(stage);
pressed = false;
button.addListener(new ClickListener() {
@Override
public boolean touchDown(InputEvent event, float x, float y, int pointer, int button) {
pressed = true;
return true;
}
@Override
public void touchUp(InputEvent event, float x, float y, int pointer, int button) {
pressed = false;
}
@Override
public void exit(InputEvent event, float x, float y, int pointer, Actor toActor) {
System.out.println("exited");
}
});
}
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编辑:
将鼠标悬停在按钮上也不会改变按钮的纹理,因为我将其设置为如此:
buttonStyle.over = skin.getDrawable("over");
但点击确实.
搜索了几个小时后,我终于找到了遗漏的东西.stage.act();必须在render方法中调用.当我们将鼠标悬停在按钮上以及InputListener中的enter/exit方法时,这两者都为纹理更改提供了功能.