C++ 11嵌套映射与列表初始化

Question

我有一个嵌套的地图,即map<int, map<int, string>>我想用初始化列表初始化.我可以使用初始化列表来初始化单级映射,但似乎无法找出嵌套映射的正确语法.它甚至可能吗？

MWE:

// This example shows how to initialize some maps
// Compile with this command:
//      clang++ -std=c++11 -stdlib=libc++ map_initialization.cpp -o map_initialization

#include <iostream>
#include <map>
#include <string>

using namespace std;

int main(){
    cout << "\nLearning map initialization.\n" << endl;

    map<int, string> level1map = {
        {1, "a"},
        {2, "b"},
        {3, "c"}
    };

    for (auto& key_value : level1map) {
        cout << "key: " << key_value.first << ", value=" << key_value.second << endl;
    }

//  This section doesn't compile
//  map<int, map<int, string>> level2map = {
//      {0,
//          {0, "zero"},
//          {1, "one"},
//          {2, "two"}
//      },

//      {1,
//          {0, "ZERO"},
//          {1, "ONE"},
//          {2, "TWO"}
//      }
//  };

    return 0;
}

Answer 1

你只是在内部地图内容周围缺少一对括号:

map<int, map<int, string>> level2map = {
    {0, {
        {0, "zero"},
        {1, "one"},
        {2, "two"}
    }},

    {1, {
        {0, "ZERO"},
        {1, "ONE"},
        {2, "TWO"}
    }}
};

如果你用一行写出来,也许会更加引人注目.四个列表:

{0, {0, "zero"}, {1, "one"}, {2, "two"}}

与2件事的清单相比,第二件事是3件事的清单:

{0, {{0, "zero"}, {1, "one"}, {2, "two"}}}