C++指针地址解释

Question

我是C++的新手,我有一段这样的代码:

int firstvalue=10;
int * mypointer;
mypointer = &firstvalue;
cout << "pointer is " << *mypointer << '\n';
cout << "pointer is " << mypointer << '\n';
cout << "pointer is " << &mypointer << '\n';

结果是:

pointer is 10
pointer is 0x7ffff8073cb4
pointer is 0x7ffff8073cb8

任何人都可以向我解释为什么"mypointer"和"&mypointer"的结果不同？

非常感谢.

Answer 1

• mypointer是变量的值mypointer.由于你的任务,这个价值是地址firstvalue.
• &mypointer是变量的地址mypointer.也就是地址mypointer.

那么,mypointer是地址firstvalue,&mypointer是地址mypointer.由于firstvalue和mypointer是不同的变量,它们具有不同的地址.