在具有接口{}值的地图上实现String()

Question

我怎么能写一个函数来在Go(Golang)中打印一个地图对象？现在我有这个,但它没有编译.它回来了cannot convert value (type interface {}) to type reflect.Kind: need type assertion.

package main

type MyDictionary map[string]interface{}

func (d MyDictionary) String() string {
    var stringBuffer bytes.Buffer

    for key, value := range d {
        stringBuffer.WriteString(key)
        stringBuffer.WriteString(": ")

        valueType := reflect.Kind(value)

        switch valueType {
        case reflect.String:
            log.Println("string") // just to check if this block gets executed
            // Add to stringBuffer

        case reflect.Float64:
            log.Println("float64") // just to check if this block gets executed
            // Add to stringBuffer

        default:
            log.Println("Error: type was", valueType)
        }
    }

    return stringBuffer.String()
}

func main() {
    var dict MyDictionary = make(MyDictionary)
    dict["hello"] = "world"
    dict["floating"] = 10.0
    dict["whole"] = 12

    fmt.Println(dict)
}

我想要String()返回一个字符串hello: world\nfloating: 10.0\nwhole: 12\n.然后我可以传递fmt.Println()打印这个.在Java中,我会用StringBuilder它.

hello: world
floating: 10.0
whole: 12

我也尝试value.(type)使用case string:和case float64,但后来我不知道如何写这些值stringBuffer.

Answer 1

这是一个惯用的解决方案.

func (d MyDictionary) String() string {
    var buf bytes.Buffer

    for k, v := range d {
        buf.WriteString(k + ": ")

        // v is an interface{} here
        switch v := v.(type) {
        // The inner v is typed. It shadows the outer interface{} v. That's
        // the idiomatic part.
        case string:
            buf.WriteString(v + "\n") // v is a string
        case int:
            buf.WriteString(fmt.Sprintln(v)) // v is an int
        case float64:
            buf.WriteString(fmt.Sprintln(v)) // v is a float64
        }
    }

    return buf.String()
}