bor*_*n49 8 optimization sse simd
我有以下问题:
在__m128i寄存器中,按以下顺序排列有16个8位值:
[ 1, 5, 9, 13 ] [ 2, 6, 10, 14] [3, 7, 11, 15] [4, 8, 12, 16]
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我想要实现的是有效地改组字节以获得这种排序:
[ 1, 2, 3, 4 ] [ 5, 6, 7, 8] [9, 10, 11, 12] [13, 14, 15, 16]
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它实际上类似于4x4矩阵转置,但在一个寄存器内的8位元件上运行.
您能不能指出哪种SSE(优先<= SSE2)指令适合实现这一点?
你真的想要去SSSE3,它比试图去<= SSE2要干净得多
您的代码看起来像这样:
#include <tmmintrin.h> // _mm_shuffle_epi8
#include <tmmintrin.h> // _mm_set_epi8
...
// check if your hardware supports SSSE3
...
__m128i mask = _mm_set_epi8(15, 11, 7, 3,
14, 10, 6, 2,
13, 9, 5, 1,
12, 8, 4, 0);
__m128i mtrx = _mm_set_epi8(16, 12, 8, 4,
15, 11, 7, 3,
14, 10, 6, 2,
13, 9, 5, 1);
mtrx = _mm_shuffle_epi8(mtrx, mask);
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如果你真的想要SSE2就足够了:(
假设我正确地解释了你的初始订购)
__m128i mask = _mm_set_epi8(0x00, 0xFF, 0x00, 0xFF,
0x00, 0xFF, 0x00, 0xFF,
0x00, 0xFF, 0x00, 0xFF,
0x00, 0xFF, 0x00, 0xFF);
__m128i mtrx = _mm_set_epi8(16, 12, 8, 4,
15, 11, 7, 3,
14, 10, 6, 2,
13, 9, 5, 1); // [1, 5, 9, 13] [2, 6, 10, 14] [3, 7, 11, 15] [ 4, 8, 12, 16]
mtrx = _mm_packus_epi16(_mm_and_si128(mtrx, mask), _mm_srli_epi16(mtrx, 8)); // [1, 9, 2, 10] [3, 11, 4, 12] [5, 13, 6, 14] [ 7, 15, 8, 16]
mtrx = _mm_packus_epi16(_mm_and_si128(mtrx, mask), _mm_srli_epi16(mtrx, 8)); // [1, 2, 3, 4] [5, 6, 7, 8] [9, 10, 11, 12] [13, 14, 15, 16]
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或者更容易调试:
__m128i mtrx = _mm_set_epi8(16, 12, 8, 4,
15, 11, 7, 3,
14, 10, 6, 2,
13, 9, 5, 1); // [1, 5, 9, 13] [ 2, 6, 10, 14] [ 3, 7, 11, 15] [ 4, 8, 12, 16]
__m128i mask = _mm_set_epi8(0x00, 0xFF, 0x00, 0xFF,
0x00, 0xFF, 0x00, 0xFF,
0x00, 0xFF, 0x00, 0xFF,
0x00, 0xFF, 0x00, 0xFF);
__m128i temp = _mm_srli_epi16(mtrx, 8); // [5, 0, 13, 0] [ 6, 0, 14, 0] [ 7, 0, 15, 0] [ 8, 0, 16, 0]
mtrx = _mm_and_si128(mtrx, mask); // [1, 0, 9, 0] [ 2, 0, 10, 0] [ 3, 0, 11, 0] [ 4, 0, 12, 0]
mtrx = _mm_packus_epi16(mtrx, temp); // [1, 9, 2, 10] [ 3, 11, 4, 12] [ 5, 13, 6, 14] [ 7, 15, 8, 16]
temp = _mm_srli_epi16(mtrx, 8); // [9, 0, 10, 0] [11, 0, 12, 0] [13, 0, 14, 0] [15, 0, 16, 0]
mtrx = _mm_and_si128(mtrx, mask); // [1, 0, 2, 0] [ 3, 0, 4, 0] [ 5, 0, 6, 0] [ 7, 0, 8, 0]
mtrx = _mm_packus_epi16(mtrx, temp); // [1, 2, 3, 4] [ 5, 6, 7, 8] [ 9, 10, 11, 12] [13, 14, 15, 16]
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