HQL意外的AST节点:{vector}

rcg*_*e23 9 java grails hibernate hql

我正在尝试编写一个HQL查询来获取属于特定组织的用户列表,或者来自特许经营者列表中的任何特许经营者,但是hibernate无法解析它.我无法弄清楚为什么.这是HQL:

from User u where 
(u.parentOrganisation = :topLevelOrganisation or u.parentOrganisation in :franchisees) 
and u.parentOrganisation.deleted = false 
and u.active = true
Run Code Online (Sandbox Code Playgroud)

这是hibernate吐出的错误:

unexpected AST node: {vector} [from com.myapp.User u where (u.parentOrganisation = :topLevelOrganisation or u.parentOrganisation in :franchisees0_, :franchisees
1_, :franchisees2_) and u.parentOrganisation.deleted = false and u.active = true]. Stacktrace follows:
Message: unexpected AST node: {vector} [from com.myapp.User u where (u.parentOrganisation = :topLevelOrganisation or u.parentOrganisation in :franchisees0_, :fr
anchisees1_, :franchisees2_) and u.parentOrganisation.deleted = false and u.active = true]
Run Code Online (Sandbox Code Playgroud)

如果我取出这个or u.parentOrganisation in :franchisees位,那么我的查询看起来像这样:

from User u where 
(u.parentOrganisation = :topLevelOrganisation) 
and u.parentOrganisation.deleted = false 
and u.active = true
Run Code Online (Sandbox Code Playgroud)

然后它工作正常.我的语法有什么问题?为什么hibernate抱怨这个额外的子句?

rcg*_*e23 29

哦,事实证明我需要括:franchisees在括号中:

from User u where 
(u.parentOrganisation = :topLevelOrganisation or u.parentOrganisation in (:franchisees)) 
and u.parentOrganisation.deleted = false 
and u.active = true
Run Code Online (Sandbox Code Playgroud)


Jak*_*sić 6

发生这种情况的原因是,当将数组中的数据放在列表中且没有括号时,用于从列表中搜索数据库的查询语法将是错误的。

例:

List<Integer> userIdList = [0, 1, 2, 3]
Run Code Online (Sandbox Code Playgroud)

查询不带括号: from User u where u.id in :list

看起来是这样的数据插入时from User u where u.id in 0, 1, 2, 3- 语法错误

用括号查询: from User u where u.id in (:list)

插入数据时将如下所示from User u where u.id in (0, 1, 2, 3)- 正确语法