如何在Python中实现"if if"？

Question

我想在概念上实现以下内容:

if condition1:
    action1()
also if condition2:
    action2()
also if condition3:
    action3()
also if condition4:
    action4()
also if condition5:
    action5()
also if condition6:
    action6()
else:
    print("None of the conditions was met.")

实现这样的逻辑的合理而明确的方法是什么？如何else绑定多个if语句？我是否会被迫创建一个布尔来跟踪事物？

Answer 1

我会建议:

if condition1:
    action1()
if condition2:
    action2()
...
if not any(condition1, condition2, ...):
    print(...)

Answer 2

好的,根据澄清,这样的事情会很好:

class Accumulator(object):
    none = None
    def also(self, condition):
        self.none = not condition and (self.none is None or self.none)
        return condition

acc = Accumulator()
also = acc.also

if also(condition1):
    action1()
if also(condition2):
    action2()
if also(condition3):
    action3()
if also(condition4):
    action4()
if acc.none:
    print "none passed"

您可以扩展它以获取有关if语句执行的其他信息:

class Accumulator(object):
    all = True
    any = False
    none = None
    total = 0
    passed = 0
    failed = 0

    def also(self, condition):
        self.all = self.all and condition
        self.any = self.any or condition
        self.none = not condition and (self.none is None or self.none)
        self.total += 1
        self.passed += 1 if condition else self.failed += 1 
        return condition

Answer 3

conditionMet = False
if condition1:
    action1()
    conditionMet = True
if condition2:
    action2()
    conditionMet = True
if condition3:
    action3()
    conditionMet = True
if condition4:
    action4()
    conditionMet = True
if condition5:
    action5()
    conditionMet = True
if condition6:
    action6()
    conditionMet = True

if not conditionMet:
    print("None of the conditions was met.")