ProgressBar不会停止

Question

我已经创建了一个应用程序,其中用户登录他的帐户.为此我使用asyncTask.Everything工作正常,但事情是当我得到响应,我希望进度条停止.但它继续下去.

异步任务

protected void onPreExecute() {
        super.onPreExecute ();
        CommonFunctions.showProgress (c, "Please Wait", true);
    }

    @Override
    protected void onPostExecute(String s) {
        super.onPostExecute (s);
        try {
            JSONObject jsonObject = new JSONObject (s.trim ());
            JSONObject NewDataSet = jsonObject.getJSONObject ("NewDataSet");
            JSONObject Table = NewDataSet.getJSONObject ("Table");
            String User_ID = Table.getString ("User_ID");
            String Vendor_IEntity_Code = Table.getString ("Vendor_IEntity_Code");
            String Vendor_Name = Table.getString ("Vendor_Name");


            // setting the preferences
            SettingPreference.setUserId (c, User_ID);
            SettingPreference.setVendorId (c, Vendor_IEntity_Code);
            SettingPreference.setVendorName (c, Vendor_Name);

        } catch (JSONException e) {
            e.printStackTrace ();
        }
        CommonFunctions.showProgress (c, "", false);

        Crouton.makeText ((android.app.Activity) c, "Login Sucessful", Style.CONFIRM).show ();

    }

    @Override
    protected String doInBackground(String... strings) {
        response = HttpRequest.post ("https://beta135.hamarisuraksha.com/web/WebService/HsJobService.asmx/IsUserValid").send ("_UserID=" + strings[0] + "&_Password=" + strings[1]).body ();
        Log.e ("Login Response", "" + response);
        return response;
    }  

CommonFunctions

public class CommonFunctions {

    private Context c;


    public static void showProgress(Context context, String message, boolean isVisible) {

        ProgressDialog progressDialog = new ProgressDialog (context);
        progressDialog.setMessage (message);
        progressDialog.setCancelable (false);
        if (isVisible) {
            progressDialog.show ();
        } else if (isVisible == false) {
            if (progressDialog.isShowing ()) {
                progressDialog.dismiss ();
            }
        }
    }
}

Answer 1

问题:

ProgressDialog progressDialog = new ProgressDialog (context);

因此,每次调用showProgress方法时,您都在创建一个新方法,ProgressDialog因此在再次调用该方法时不会解雇.

解:

仅创建一次实例 ProgressDialog

public class CommonFunctions {

    private Context c;
    ProgressDialog progressDialog;


    public static void showProgress(Context context, String message, boolean isVisible) {

        if(progressDialog == null)
        {
             progressDialog = new ProgressDialog (context);
             progressDialog.setMessage (message);
             progressDialog.setCancelable (false);
        }

        if (isVisible) {
            progressDialog.show();
        } else if (isVisible == false) {
            if (progressDialog.isShowing ()) {
                progressDialog.dismiss();
                progressDialog = null;
            }
       }
    }
}