跟踪Erlang函数 - 简短形式

Rob*_*loi 4 debugging erlang trace

您可能知道,现在可以使用简短形式跟踪Erlang函数:

dbg:tpl(Module, Function, x).
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而不是通常的:

dbg:tpl(Module, Function, dbg:fun2ms(fun(_) -> exception_trace() end)).
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我其实想知道是否有类似的简短形式return_trace().就像是:

dbg:tpl(Module, Function, r).
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代替:

dbg:tpl(Module, Function, dbg:fun2ms(fun(_) -> return_trace() end)).
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dbg模块中的源代码似乎不建议:

new_pattern_table() ->
    PT = ets:new(dbg_tab, [ordered_set, public]),
    ets:insert(PT, 
           {x, 
        term_to_binary([{'_',[],[{exception_trace}]}])}),
    ets:insert(PT, 
           {exception_trace, 
        term_to_binary(x)}),
    PT.
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但我可能错了.你知道吗?

leg*_*cia 5

不是真的,但你可以记住saved结果中的数字dbg:tpl并重复使用它:

1> dbg:tracer().
{ok,<0.33.0>}
2> dbg:p(all,c).
{ok,[{matched,nonode@nohost,25}]}
3> dbg:tpl(lists, sort, dbg:fun2ms(fun(_) -> return_trace() end)).
{ok,[{matched,nonode@nohost,2},{saved,1}]}
4> dbg:tpl(lists, sum, 1).
{ok,[{matched,nonode@nohost,2},{saved,1}]}
5> lists:sum([1,2,3]).
6
6> (<0.31.0>) call lists:sum([1,2,3])
(<0.31.0>) call lists:sum([1,2,3],0)
(<0.31.0>) call lists:sum([2,3],1)
(<0.31.0>) call lists:sum([3],3)
(<0.31.0>) call lists:sum([],6)
(<0.31.0>) returned from lists:sum/2 -> 6
(<0.31.0>) returned from lists:sum/2 -> 6
(<0.31.0>) returned from lists:sum/2 -> 6
(<0.31.0>) returned from lists:sum/2 -> 6
(<0.31.0>) returned from lists:sum/1 -> 6
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