hac*_*ife 0 javascript arrays jquery json
联系到这个问题,并且这其中也,我想知道如何做同样的事情,但有一个不同类型的JSON的:
这是我的JSON对象:
var myDb = {
"04c85ccab52880": {
"name": "name1",
"firstname": "fname1",
"societe": "soc1"
},
"04c95ccab52880": {
"name": "name2",
"firstname": "fname2",
"societe": "soc2"
},
"048574220e2a80": {
"name": "name3",
"firstname": "fname3",
"societe": "soc3"
}
};
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我的问题是我的JSON与他们的JSON不同,实际上我有一个数组数组.那么如何将其转换为Javascript数组呢?
var arr = [];
$.each( myDb, function( key, value ) {
arr.push( value );
});
console.log(user_list);
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这种脚本似乎返回了我的3个不同的对象但是我的uid来自JSON?我怎么能得到它们?因为现在我的钥匙是0,1,2而不再是我的uid.
有任何想法吗 ?谢谢
一个有效的JSFIDDLE
JS代码:
//var arr = [];
var myDb = {
"04c85ccab52880": {
"name": "name1",
"firstname": "fname1",
"societe": "soc1"
},
"04c95ccab52880": {
"name": "name2",
"firstname": "fname2",
"societe": "soc2"
},
"048574220e2a80": {
"name": "name3",
"firstname": "fname3",
"societe": "soc3"
}
};
$.each( myDb, function( key, value ) {
//arr.push( value );
console.log("key => "+key);//will output: 04c85ccab52880 and all such
$.each( value, function( ky, val ) {
console.log('ky => '+ky);//will output: name, firstname, societe
console.log('val => '+val);//will output: name1, fname1, soc1
});
});
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