嵌套的Switch语句

Question

目前我正在尝试创建一个程序,它将从头开始自动生成一个完整的数独板,虽然相同的功能可以通过微小的改动来解决部分填充的数独板.问题是,当你在板上加载一个新的数字时,你显然必须检查这个数字是否已经存在于同一列或行中,而且也是在加载它的3x3方块中.对程序的一部分使用嵌套的switch语句,你必须根据相同的3x3方格中的数字检查数字,尽管break语句都显示在正确的位置.compliler说的是第二个case语句的第一个数字,它是嵌套switch语句的一部分:"Error:case标签值已经出现在这个开关中",即使数字没有,问题是为什么？

这是代码:

bool SudokuClass::checkPresentGrid(int &temporary, int row, int column)
{
bool indicator;
 switch (row)
{
case 0 || 3 || 6:       //If the number is being loaded into row 0,3 or 6
    switch (column)
    {
    case 0 || 3 || 6:   //Check all other spaces in the same 3x3 grid   
        if (temporary == (completeSudoku[row + 1][column + 1] || completeSudoku[row + 1][column + 2] || completeSudoku[row + 2][column + 1] || completeSudoku[row + 2][column + 2]))
        {
            indicator = true;
        }
        break;
    case 1 || 4 || 7:
        if (temporary == (completeSudoku[row + 1][column - 1] || completeSudoku[row + 1][column + 1] || completeSudoku[row + 2][column - 1] || completeSudoku[row + 2][column + 1]))
        {
            indicator = true;
        }
        break;
    case 2 || 5 || 8:
        if (temporary == (completeSudoku[row + 1][column - 2] || completeSudoku[row + 1][column - 1] || completeSudoku[row + 2][column - 2] || completeSudoku[row + 2][column - 1]))
        {
            indicator = true;
        }
        break;
    }
    break;
case 1 || 4 || 7:               //If the number is being loaded into row 1, 4 or 7
    switch (column)
    {
    case 0 || 3 || 6:   //Check all other spaces in the same 3x3 grid   
        if (temporary == (completeSudoku[row - 1][column + 1] || completeSudoku[row - 1][column + 2] || completeSudoku[row + 1][column + 1] || completeSudoku[row + 1][column + 2]))
        {
            indicator = true;
        }
        break;
    case 1 || 4 || 7:
        if (temporary == (completeSudoku[row - 1][column - 1] || completeSudoku[row - 1][column + 1] || completeSudoku[row + 1][column - 1] || completeSudoku[row + 1][column + 1]))
        {
            indicator = true;
        }
        break;
    case 2 || 5 || 8:
        if (temporary == (completeSudoku[row - 1][column - 2] || completeSudoku[row - 1][column - 1] || completeSudoku[row + 1][column - 2] || completeSudoku[row + 1][column - 1]))
        {
            indicator = true;
        }
        break;
    }
    break;
case 2 || 5 || 8:               //If the number is being loaded into row 2, 5 or 8
    switch (column)
    {
    case 0 || 3 || 6:           //Check all other spaces in the same 3x3 grid   
        if (temporary == (completeSudoku[row - 2][column + 1] || completeSudoku[row - 2][column + 2] || completeSudoku[row - 1][column + 1] || completeSudoku[row - 1][column + 2]))
        {
            indicator = true;
        }
        break;
    case 1 || 4 || 7:
        if (temporary == (completeSudoku[row - 2][column - 1] || completeSudoku[row - 2][column + 1] || completeSudoku[row - 1][column - 1] || completeSudoku[row - 1][column + 1]))
        {
            indicator = true;
        }
        break;
    case 2 || 5 || 8:
        if (temporary == (completeSudoku[row - 2][column - 2] || completeSudoku[row - 2][column - 1] || completeSudoku[row - 1][column - 2] || completeSudoku[row - 1][column - 1]))
        {
            indicator = true;
        }
        break;
    }
    break;
}
return indicator;

}

Answer 1

更改

case 0 || 3 || 6:       //If the number is being loaded into row 0,3 or 6

至

case 0:
case 3:
case 6:       //If the number is being loaded into row 0,3 or 6

......等等,还有你的其他case陈述.

你的代码 case 0 || 3 || 6

被评估为 case (0 || 3 || 6)

变成了 case (false || true || true)

变成了case (true),这不是你想要的.