我已经通过了测试,所以代码工作它真的看起来有点难看有点unRuby,有没有更多的Ruby方式.
这是我的解决方案
def start_of_word(word, x=1)
@word = word[0,1+(x-1)]
end
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这些都是通过的考验
describe "start_of_word" do
it "returns the first letter" do
start_of_word("hello", 1).should == "h"
end
it "returns the first two letters" do
start_of_word("Bob", 2).should == "Bo"
end
it "returns the first several letters" do
s = "abcdefg"
start_of_word(s, 1).should == "a"
start_of_word(s, 2).should == "ab"
start_of_word(s, 3).should == "abc"
end
end
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1+(x-1)是等于x.
def start_of_word(word, x=1)
word[0, x]
end
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分配给@word没有必要通过测试.
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