Cla*_*nei 1 java lambda java-8
可以在Lambda中执行此操作:
for (final WarehouseAddress address : warehouse.getAddresses()) {
if (!Validator.isEmpty(address.getPositions())) {
final Set<WarehouseAddressPosition> positions = new HashSet<WarehouseAddressPosition>(
address.getPositions());
if (address.getPositions().size() > positions.size()) {
throw new FieldDuplicatedException("position error");
}
}
}
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我试过没有成功:
final Set<WarehouseAddressPosition> positions = warehouse.getAddresses().stream().filter(a -> !Validator.isEmpty(a.getPositions())).collect(
Collectors.toSet());
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因为他试图收集一套WarehouseAdress而不是一套WarehouseAdressPosition.
错误:(130,156)java:不兼容类型:推理变量T具有不兼容的边界等式约束:br.com.erp.ejb.entity.sales.WarehouseAddressPosition下限:br.com.erp.ejb.entity.sales.WarehouseAddress
在Warehouse类我有:
private List<WarehouseAddress> addresses;
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在WarehouseAddress类中,我有:
private List<WarehouseAddressPosition> positions;
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说明:此代码获取位置的原始列表并将其收集在Set中,以创建没有重复值的集合并将大小与原始列表进行比较,以检查它是否重复.由于Set不接受重复值,因此在这种情况下大小将不同.
如果我理解正确,你想收集WarehouseAddressPosition,而不是WarehouseAddress,所以你需要:
final Set<WarehouseAddressPosition> positions =
warehouse.
getAddresses().
stream().
filter(a -> !Validator.isEmpty(a.getPositions())).
flatMap(a -> a.getPositions().stream()).
collect(Collectors.toSet());
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如果你希望当你遇到复制失败的过程WarehouseAddressPosition中同WarehouseAddress,我建议改变private List<WarehouseAddressPosition> positions成为一个集.这样,您可以在收集所有地址的位置之前找到此类重复项.
如果您有充分的理由不进行此更改,您可以在filter步骤中进行相同的重复检查(目前在原始代码中完成)(我希望我的语法正确,因为我现在无法检查它) :
final Set<WarehouseAddressPosition> positions =
warehouse.
getAddresses().
stream().
filter(a -> if (!Validator.isEmpty(a.getPositions())) {
final Set<WarehouseAddressPosition> positions = new HashSet<WarehouseAddressPosition>(
a.getPositions());
if (a.getPositions().size() > positions.size()) {
throw new FieldDuplicatedException("position error");
} else {
return true;
}
} else {
return false;
}).
flatMap(a -> a.getPositions().stream()).
collect(Collectors.toSet());
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