PHP多字符串比较

Question

我想检查6个字符串是否不一样.我试过这个:

if($first != $second != $third != $four != $fifth != $sixth){}

但我收到错误:

Parse error: syntax error, unexpected '!=' (T_IS_NOT_EQUAL)

我不知道任何能做同样事情的功能.

Answer 1

if (count(array_unique(array($first, $second, $third, $fourth, $fifth, $sixth)) == 6) {
    echo 'All different';
}