如何在NSUserDefaults中写入/获取"long long int"

Question

在我的应用程序中,我有long long int变量:9999999999我需要编写它,然后将其传入/传出NSUserDefaults.方法setInteger:forKey:并integerForKey:不起作用.谢谢!

Answer 1

将整数包装到NSNumber对象中并使用setObject:forKey::

long long int val = 9999999999LL;
[[NSUserDefaults standardUserDefaults]  setObject:@(val) forKey:@"key"];

检索值:

long long int val = [[[NSUserDefaults standardUserDefaults] objectForKey:@"key"] longLongValue];