Ala*_*eng 2 mongodb mongodb-query aggregation-framework
我有类似于存储在mongodb中的文档
{
"_id":"transaction_id"
"customer":"some customer",
"order_date":Date('2011-01-01'),
"delivery_date":Date('2011-01-15'),
"amt":500.0,
"qty":50
},
{
"_id":"transaction_id"
"customer":"some customer",
"order_date":Date('2011-01-01'),
"delivery_date":Date('2011-02-04'),
"amt":500.0,
"qty":50
}
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我希望对订单日期和交货日期进行一些汇总,以绘制每月订购和交付给每个客户的库存总量.
当然,我可以运行2个聚合查询来获得我想要的东西,但我只是想知道是否有可能获得具有2组具有1个命令的结果?
预期结果如下:
results:[{
_id:{
customer:"some customer"
},
orders:[
{
year:2011,
month:1,
qty:100
},
...
]
deliveries:[
{
year:2011,
month:1,
qty:50
},
{
year:2011,
month:2,
qty:50
},
...
]
},...]
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小智 9
我遇到了类似的问题,其中我需要将结果分类为多个组,查看所有这些答案让我头晕目眩。经过大量研究后,我找到了我正在寻找的确切东西。
MongoDB 在 3.4 版本中引入了一个名为$facet的新命令,这使得在单个命令中包含多个组变得非常容易。看看他们的文档:
我本来打算在这里用文字解释这一切,但我认为他们的文档更清晰,写得更漂亮,有很好的例子。
希望能帮助到你。
您可以在一个查询中执行此操作,您只需要在操作文档时有点创意,然后基本上执行两个 $group阶段,首先按日期添加,然后按客户添加.
因此,首先使用当前的MongoDB版本2.6及更高版本,因为使用了一些运算符:
db.transactions.aggregate([
// Project an additional array, stands for "order", "delivery"
{ "$project": {
"_id": 0,
"customer": 1,
"order_date": 1,
"delivery_date": 1,
"qty": 1,
"type": { "$literal": ["o","d"] }
}},
// Unwind that array, creates two documents by "type"
{ "$unwind": "$type" },
// Group by "customer", "type" and date
{ "$group": {
"_id": {
"customer": "$customer",
"type": "$type",
"year": {
"$year": {
"$cond": [
{ "$eq": [ "$type", "o" ] },
"$order_date",
"$delivery_date"
]
}
},
"month": {
"$month": {
"$cond": [
{ "$eq": [ "$type", "o" ] },
"$order_date",
"$delivery_date"
]
}
}
},
"qty": { "$sum": "$qty" }
}},
// Group on the "customer" selecting which array to add to
{ "$group": {
"_id": "$_id.customer",
"orders": {
"$push": {
"$cond": [
{ "$eq": [ "$_id.type", "o" ] },
{
"year": "$_id.year",
"month": "$_id.month",
"qty": "$qty"
},
false
]
}
},
"deliveries": {
"$push": {
"$cond": [
{ "$eq": [ "$_id.type", "d" ] },
{
"year": "$_id.year",
"month": "$_id.month",
"qty": "$qty"
},
false
]
}
}
}},
// Getting rid of the `false` values in there
{ "$project": {
"orders": { "$setDifference": [ "$orders", [false] ] },
"deliveries": { "$setDifference": [ "$deliveries", [false] ] },
}},
// But "sets" are not considered ordered, so sort them
{ "$unwind": "$orders" },
{ "$sort": { "orders.year": 1, "orders.month": 1 } },
{ "$group": {
"_id": "$_id",
"orders": { "$push": "$orders" },
"deliveries": { "$first": "$deliveries" }
}},
{ "$unwind": "$deliveries" },
{ "$sort": { "deliveries.year": 1, "deliveries.month": 1 } },
{ "$group": {
"_id": "$_id",
"orders": { "$first": "$orders" },
"deliveries": { "$push": "$deliveries" }
}}
)
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对于2.6之前的版本,这样做有点不同:
db.transactions.aggregate([
// Project an additional array, stands for "order", "delivery"
{ "$project": {
"_id": 0,
"customer": 1,
"order_date": 1,
"delivery_date": 1,
"qty": 1,
"type": { "$cond": [ 1, ["o","d"], 0 ] }
}},
// Unwind that array, creates two documents by "type"
{ "$unwind": "$type" },
// Group by "customer", "type" and date
{ "$group": {
"_id": {
"customer": "$customer",
"type": "$type",
"year": {
"$year": {
"$cond": [
{ "$eq": [ "$type", "o" ] },
"$order_date",
"$delivery_date"
]
}
},
"month": {
"$month": {
"$cond": [
{ "$eq": [ "$type", "o" ] },
"$order_date",
"$delivery_date"
]
}
}
},
"qty": { "$sum": "$qty" }
}},
// Group on the "customer" selecting which array to add to
{ "$group": {
"_id": "$_id.customer",
"orders": {
"$push": {
"$cond": [
{ "$eq": [ "$_id.type", "o" ] },
{
"year": "$_id.year",
"month": "$_id.month",
"qty": "$qty"
},
false
]
}
},
"deliveries": {
"$push": {
"$cond": [
{ "$eq": [ "$_id.type", "d" ] },
{
"year": "$_id.year",
"month": "$_id.month",
"qty": "$qty"
},
false
]
}
}
}},
// Filter `false` and sort on date
{ "$unwind": "$orders" },
{ "$match": { "orders": { "$ne": false } } },
{ "$sort": { "orders.year": 1, "orders.month": 1 } },
{ "$group": {
"_id": "$_id",
"orders": { "$push": "$orders" },
"deliveries": { "$first": "$deliveries" }
}},
{ "$unwind": "$deliveries" },
{ "$match": { "deliveries": { "$ne": false } } },
{ "$sort": { "deliveries.year": 1, "deliveries.month": 1 } },
{ "$group": {
"_id": "$_id",
"orders": { "$first": "$orders" },
"deliveries": { "$push": "$deliveries" }
}}
])
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基本上总结这里的方法,你正在做的是复制每个文档并分配一个代表"订单"或"交付"的"类型".然后,当您按"客户"和"日期"和"类型"进行分组时,您有条件地根据当前类型决定选择哪个"日期",并只是总结该键下的"数量".
由于结果是每个客户的"订单"和"交付"数组,因此您有条件$push地将该文档值或文档值false取决于文档的当前"类型"对每个数组.
最后,由于这些数组现在包含false所需文档的值以及过滤掉这些值,并确保您的数组按照正确的"日期"顺序排列.
是的,列表有两个以上的$group阶段,繁重的实际上是在两个分组中完成,其他分组只是在那里进行数组操作,如果你需要它,但它给你精确和有序的结果.
所以这可能不是您可能想到的第一种方法,但展示了一些有趣的转换思路,您可以将它们与各种聚合运算符一起使用以解决问题.这是做:)
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