如何将长的红宝石哈希分成多行？

Question

我有这个哈希：

  arr={ [0,1]=>[0,0,1,1], [0,2]=>[0,1,0,1], [0,3]=>[0,1,1,0], [1,2]=>[1,0,0,1], [1,3] =>[1,0,1,0], [2,3] => [1,1,0,0] }

我想把它分成两行，因为它很长，为121个字符。我不是线条长度的标签，但我的指导线是80，比我喜欢的更长

所以我尝试了

  arr={ [0,1] => [0,0,1,1], [0,2] => [0,1,0,1], [0,3] => [0,1,1,0] }
  arr.merge({[1,2] => [1,0,0,1], [1,3] => [1,0,1,0], [2,3] => [1,1,0,0]})

但是我的测试失败了，并出现诸如

undefined method `[]' for nil:NilClass

我该如何更好地分解？一种选择是连续行，\但看上去并不太整齐。

arr={ [0,1]=>[0,0,1,1], [0,2]=>[0,1,0,1], [0,3]=>[0,1,1,0], \
[1,2]=>[1,0,0,1], [1,3] =>[1,0,1,0], [2,3] => [1,1,0,0] }

虽然我想我可以做

arr={ [0,1]=>[0,0,1,1], [0,2]=>[0,1,0,1], [0,3]=>[0,1,1,0], \
      [1,2]=>[1,0,0,1], [1,3] =>[1,0,1,0], [2,3] => [1,1,0,0] }

但这看起来像是空白维护缩进的气味。

有更整洁的选择吗？

Answer 1

arr = {
  [0,1] => [0,0,1,1], [0,2] => [0,1,0,1], [0,3] => [0,1,1,0],
  [1,2] => [1,0,0,1], [1,3] => [1,0,1,0], [2,3] => [1,1,0,0]
}

Answer 2

我更愿意这样写：

arr = { 
  [0,1] => [0,0,1,1],
  [0,2] => [0,1,0,1],
  [0,3] => [0,1,1,0],
  [1,2] => [1,0,0,1],
  [1,3] => [1,0,1,0],
  [2,3] => [1,1,0,0] 
}

它更具可读性。另外我假设您知道使用数组作为键的后果吗？