在Ratpack Groovy中解析json

shm*_*111 6 groovy json ratpack

我在Groovy控制台中启动了一个小型的ratpack应用程序,但我无法从文档中找到如何获取已在请求中发送的json数据.

@Grab("io.ratpack:ratpack-groovy:0.9.4")
import static ratpack.groovy.Groovy.*
import groovy.json.JsonSlurper

ratpack {
  handlers {
    get {
      def slurper = new JsonSlurper()
      def result = slurper.parseText('{"person":{"name":"Guillaume","age":33,"pets":["dog","cat"]}}')
      render "Hello world! ${result.person}"
    }
    post("foo") {
      def slurper = new JsonSlurper()
      def result = slurper.parseText("WHAT DO i PUT HERE?")
      render "Hello world! ${result.person}"
    }
  }
}
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一个示例请求:

curl -XPOST -H "Content-Type: application/json" -d '{"person":{"name":"Guillaume","age":33,"pets":["dog","cat"]}}' localhost:5050/foo
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Dan*_*yun 10

Ratpack提供了一个称为Parser的概念,允许您将传入的请求主体解析为给定类型.

在您的情况下,您可以使用该ratpack-jackson模块将传入的请求正文解析为JsonNode或您自己的类型.您可以在此处找到更多信息.

以下是使用ratpack-jackson模块提供的解析器的示例:

@Grab("io.ratpack:ratpack-groovy:0.9.12")     
@Grab("io.ratpack:ratpack-jackson:0.9.12")    

import static ratpack.groovy.Groovy.*         
import ratpack.jackson.JacksonModule          
import static ratpack.jackson.Jackson.jsonNode

ratpack {                                     
  bindings {                                  
    add new JacksonModule()                   
  }                                           
  handlers {                                  
    post("foo") {                             
      def postBody = parse jsonNode()
      render "Hello world! ${postBody.person}"
    }                                         
  }                                           
}                 
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你的卷曲

curl -XPOST -H "Content-Type: application/json" -d '{"person":{"name":"Guillaume","age":33,"pets":["dog","cat"]}}' localhost:5050/foo
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回复为

Hello world! {"name":"Guillaume","age":33,"pets":["dog","cat"]}
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我希望这有帮助!