shm*_*111 6 groovy json ratpack
我在Groovy控制台中启动了一个小型的ratpack应用程序,但我无法从文档中找到如何获取已在请求中发送的json数据.
@Grab("io.ratpack:ratpack-groovy:0.9.4")
import static ratpack.groovy.Groovy.*
import groovy.json.JsonSlurper
ratpack {
handlers {
get {
def slurper = new JsonSlurper()
def result = slurper.parseText('{"person":{"name":"Guillaume","age":33,"pets":["dog","cat"]}}')
render "Hello world! ${result.person}"
}
post("foo") {
def slurper = new JsonSlurper()
def result = slurper.parseText("WHAT DO i PUT HERE?")
render "Hello world! ${result.person}"
}
}
}
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一个示例请求:
curl -XPOST -H "Content-Type: application/json" -d '{"person":{"name":"Guillaume","age":33,"pets":["dog","cat"]}}' localhost:5050/foo
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Dan*_*yun 10
Ratpack提供了一个称为Parser的概念,允许您将传入的请求主体解析为给定类型.
在您的情况下,您可以使用该ratpack-jackson模块将传入的请求正文解析为JsonNode或您自己的类型.您可以在此处找到更多信息.
以下是使用ratpack-jackson模块提供的解析器的示例:
@Grab("io.ratpack:ratpack-groovy:0.9.12")
@Grab("io.ratpack:ratpack-jackson:0.9.12")
import static ratpack.groovy.Groovy.*
import ratpack.jackson.JacksonModule
import static ratpack.jackson.Jackson.jsonNode
ratpack {
bindings {
add new JacksonModule()
}
handlers {
post("foo") {
def postBody = parse jsonNode()
render "Hello world! ${postBody.person}"
}
}
}
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你的卷曲
curl -XPOST -H "Content-Type: application/json" -d '{"person":{"name":"Guillaume","age":33,"pets":["dog","cat"]}}' localhost:5050/foo
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回复为
Hello world! {"name":"Guillaume","age":33,"pets":["dog","cat"]}
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我希望这有帮助!