lua脚本编写后天数的日期

Question

我是lua脚本的新手.我有一个startDate("03-05-2014"as "dd-mm-yyyy")和一个跨度的天(2)任何人都可以帮助我如何得到endDate基于startDate和span？

Example startDate     span            endDate 
        ---------     ----            -------
        03-05-2014     2             05-05-2014
       (dd-mm-yyyy)                 (dd-mm-2014)

Answer 1

你不需要在这里做任何数学.os.time并os.date会为你做.

local day, month, year = ("03-05-2014"):match("(%d%d)-(%d%d)-(%d%d%d%d)")
local span = 64
local endtime = os.time({day = day + span, month = month, year = year})
print(os.date("%c", endtime))

Answer 2

这可以帮助你

local dayValue, monthValue, yearValue = string.match('31-05-2014', '(%d%d)-(%d%d)-(%d%d%d%d)')
dayValue, monthValue, yearValue = tonumber(dayValue), tonumber(monthValue), tonumber(yearValue)
now = os.time{year = yearValue, month = monthValue, day = dayValue}
numberOfDays = now + 2 * 24 * 3600
print(os.date("%c",numberOfDays))
dateAfterNumberOfDays = os.date("%a %d %B %Y, %H%p%M",numberOfDays)
print ("\nafter number of days "..dateAfterNumberOfDays) -- give you date after number of days