mysqli_query()期望至少有2个参数,1给出？

Question

每次运行这个php时,我都会得到相同的3个错误.我不知道我做错了什么,有人可以帮忙吗？

以下是错误:

[05-May-2014 19:20:50 America/Chicago] PHP警告:mysqli_query()需要至少2个参数,1在第10行的/home/sagginev/public_html/Nutrifitness/search.php中给出

[05-May-2014 19:20:50 America/Chicago] PHP警告:mysqli_num_rows()期望参数1为mysqli_result,在第11行的/home/sagginev/public_html/Nutrifitness/search.php中给出null

[05-May-2014 19:20:50 America/Chicago] PHP警告:mysqli_num_rows()期望参数1为mysqli_result,在第16行的/home/sagginev/public_html/Nutrifitness/search.php中给出null

这是我的代码

enter code here

    <?php
    $con=mysqli_connect('localhost','sagginev_rob','122989','sagginev_Nutrifitness');
    if (mysqli_connect_errno()) // Check connection
      {   echo "Failed to connect to MySQL: " . mysqli_connect_error();  }

        if(!isset($_POST['search'])) {
    header("Location:home.php");
    }
    $search_sql="Select * FROM Questions WHERE username LIKE '%".$_POST['search']."%' OR feedback LIKE '%".$_POST['search']."%'";
    $search_query=mysqli_query($search_sql);
    if(mysqli_num_rows($search_query)!=0) {
    $search_rs=mysqli_fetch_assoc($search_query);
    }
    ?>
    <H2> Search Results</H2>
    <?php if(mysqli_num_rows($search_query)!=0) {
     do { ?>
     <p><?php echo $search_rs['name']; ?> </p>
    <?php } while ($search_rs=mysqli_fetch_assoc($search_query));
    } else {
       echo "No results found";
    } ?>
    <form>
    <br>
    <input type="button" value="Go Back Home" onClick="parent.location='http://sagginevo.com/Nutrifitness/home.php'">
    </form>

Answer 1

错误信息非常清楚.mysqli_query()需要两个参数.你只提供一个.当您看到这样的错误消息时,您需要做的第一件事就是转到手册.如果你这样做,你会发现你必须提供你的MySQLi链接作为第一个参数:

$search_query=mysqli_query($con, $search_sql);